交换中值的复杂性和算法以及与其他共识问题的关系

Luís Cunha, Thiago Lopes, Arnaud Mary
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引用次数: 0

摘要

基因组重排是大块 DNA 在进化过程中交换片段的事件。对这类事件的分析是理解基因组进化的一种工具,其基础是找到将一个基因组转变为另一个基因组的最少重排次数。在一般情况下,我们需要考虑两个以上的基因组,这就给我们带来了新的挑战。{/sc中值}问题包括:在给定三个排列和一个距离度量的情况下,找到一个排列$s$,使$s$和每个输入之间的距离之和最小。我们研究的是排列组合中{emph{swap}距离的{sc中值}问题,这个问题的计算复杂度问题已经有近20年的历史了(Eriksen, \emph{Theor. Compt. Sci.},2007)。我们通过一些分支来考虑这个问题。我们把中值解和区间凸集联系起来,其中图凸性的概念启发了下面的研究:中值突变是否属于输入突变对之间的每一条最短路径?我们能够部分地回答这个问题,作为副产品,我们通过证明{交换中值}问题是 NP-hard的,解决了一个长期悬而未决的问题。此外,我们还用类似的方法证明了{\sc Closest}问题(该问题旨在最小化解与输入排列组合之间的最大距离)即使考虑三个输入排列组合也是 NP 难的。这给出了P与NP-hard方法的截然对立,因为考虑两个输入排列组合,这个问题很容易求解,而考虑任意数量的输入排列组合,这个问题自2007年以来就被认为是NP-hard的(Popov, \emph{Theor. Compt.)此外,我们还证明了 {\scSwap Median} 和 {\scSwap Closest} 是 APX 难问题。
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Complexity and algorithms for Swap median and relation to other consensus problems
Genome rearrangements are events in which large blocks of DNA exchange pieces during evolution. The analysis of such events is a tool for understanding evolutionary genomics, based on finding the minimum number of rearrangements to transform one genome into another. In a general scenario, more than two genomes are considered and we have new challenges. The {\sc Median} problem consists in finding, given three permutations and a distance metric, a permutation $s$ that minimizes the sum of the distances between $s$ and each input. We study the {\sc median} problem over \emph{swap} distances in permutations, for which the computational complexity has been open for almost 20 years (Eriksen, \emph{Theor. Compt. Sci.}, 2007). We consider this problem through some branches. We associate median solutions and interval convex sets, where the concept of graph convexity inspires the following investigation: Does a median permutation belong to every shortest path between one of the pairs of input permutations? We are able to partially answer this question, and as a by-product we solve a long open problem by proving that the {\sc Swap Median} problem is NP-hard. Furthermore, using a similar approach, we show that the {\sc Closest} problem, which seeks to minimize the maximum distance between the solution and the input permutations, is NP-hard even considering three input permutations. This gives a sharp dichotomy into the P vs. NP-hard approaches, since considering two input permutations the problem is easily solvable and considering any number of input permutations it is known to be NP-hard since 2007 (Popov, \emph{Theor. Compt. Sci.}, 2007). In addition, we show that {\sc Swap Median} and {\sc Swap Closest} are APX-hard problems.
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