关于$\sum\frac{1}{p}$的两个子级数的散度,以及de La Vall\ {e}e Poussin和Landau-Walfis的定理

IF 0.4 Q4 MATHEMATICS Boletim Sociedade Paranaense de Matematica Pub Date : 2022-12-24 DOI:10.5269/bspm.50820
G. Reddy, S. Rau, B. Uma
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引用次数: 0

摘要

设$K=Q(\sqrt{d})$是具有判别式$d$的二次域。结果表明,$\sum\limits_{(\frac{d}{p})=+1,_{p~prime}}\frac{1}{p}$和$\sum\limits_{。给出了两种不同的方法来显示分歧:一种使用Dedekind-Zeta函数,另一种使用Tauberian方法。结果表明,这两个发散是等价的。结果表明,散度等价于$L_{d}(1)\neq0$(de la Vall){e}ePoussin定理)。我们证明了序列$\sum\limits_{(\frac{d}{p})=+1,_{p~素数}}\frac{1}{p^{s}$和$\sum\limits_{q~素数}}\frag{1}{q^{s}}$在所有虚轴上都具有奇点(类似于Landau-Wallfisz定理)
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On the divergence of two subseries $\ldots$] {on the divergence of two subseries of $\sum\frac{1}{p}$, and theorems of de La Vall\'{e}e Poussin and Landau-Walfis
Let $K=Q(\sqrt{d})$ be a quadratic field with discriminant $d$. It is shown that $\sum\limits_{(\frac{d}{p})=+1,_{p~ prime}}\frac{1}{p}$ and $\sum\limits_{(\frac{d}{q})=-1,_{q~ prime}}\frac{1}{q}$ are both divergent. Two different approaches are given to show the divergence: one using the Dedekind Zeta function and the other by Tauberian methods. It is shown that these two divergences are equivalent. It is shown that the divergence is equivalent to $L_{d}(1)\neq 0$(de la Vall\'{e}e Poussin's Theorem).We prove that the series $\sum\limits_{(\frac{d}{p})=+1,_{p~ prime}}\frac{1}{p^{s}}$ and $\sum\limits_{(\frac{d}{q})=-1,_{q~ prime}}\frac{1}{q^{s}}$ have singularities on all the imaginary axis(analogue of Landau-Walfisz theorem)
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来源期刊
CiteScore
1.40
自引率
0.00%
发文量
140
审稿时长
25 weeks
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