连续函数的多项式逼近

IF 0.4 4区 数学 Q4 MATHEMATICS American Mathematical Monthly Pub Date : 2023-05-18 DOI:10.1080/00029890.2023.2206324
Sofia de la Cerda
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引用次数: 0

摘要

其中g(x)是一个递增的连续函数使得g(0) = 0和g(1 n+2) >和。如果p是一个多项式,使得||p−f ||∞< an,则对于i∈{1,2,…p, n + 2} | (xi)−f (xi) | <和f (xi) =(−1)搞笑(我)。由于g (1 i)≥g (1 n+2) > an,这意味着f (xi)和p(xi)具有相同的符号。因此,p(xi)的符号与每个i交替,并且根据中间值定理,p在区间(xi, xi+1)中有一个根。总共有n + 1个根,所以p的次数大于n,这意味着en(f) > an。b[1]中有一个等效的结构。在这里,作者使用了一个定义为无限Chebyshev多项式和的函数。
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Polynomial Approximations to Continuous Functions
where g(x) is an increasing continuous function such that g(0) = 0 and g ( 1 n+2 ) > an. If p is a polynomial such that ||p − f ||∞ < an, then for each of the points xi = i where i ∈ {1, 2, . . . , n + 2}, we have |p(xi) − f (xi)| < an and f (xi) = (−1)ig ( 1 i ) . Since g ( 1 i ) ≥ g ( 1 n+2 ) > an, this means that f (xi) and p(xi) have the same sign. Thus, the sign of p(xi) alternates with each i, and by the Intermediate Value Theorem p, has a root in the interval (xi, xi+1). This makes a total of n + 1 roots, so the degree of p is greater than n, which means that en(f ) > an. There is an equivalent construction in [1]. There, the author uses a function defined as an infinite sum of Chebyshev polynomials.
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来源期刊
American Mathematical Monthly
American Mathematical Monthly Mathematics-General Mathematics
CiteScore
0.80
自引率
20.00%
发文量
127
审稿时长
6-12 weeks
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