美术馆定理的推广

Pub Date : 2022-12-17 DOI:10.1007/s00026-022-00620-4
Peter Borg, Pawaton Kaemawichanurat
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If <span>\\(n \\le 2k+3\\)</span>, then trivially <span>\\(\\iota _k(G) \\le 1\\)</span>. Let <i>G</i> be a mop on <span>\\(n \\ge \\max \\{5,2k+3\\}\\)</span> vertices, <span>\\(n_2\\)</span> of which are of degree 2. Upper bounds on <span>\\(\\iota _k(G)\\)</span> have been obtained for <span>\\(k = 0\\)</span> and <span>\\(k = 1\\)</span>, namely <span>\\(\\iota _{0}(G) \\le \\min \\{\\frac{n}{4},\\frac{n+n_2}{5},\\frac{n-n_2}{3}\\}\\)</span> and <span>\\(\\iota _1(G) \\le \\min \\{\\frac{n}{5},\\frac{n+n_2}{6},\\frac{n-n_2}{3}\\}\\)</span>. We prove that <span>\\(\\iota _{k}(G) \\le \\min \\{\\frac{n}{k+4},\\frac{n+n_2}{k+5},\\frac{n-n_2}{k+2}\\}\\)</span> for any <span>\\(k \\ge 0\\)</span>. For the original setting of the Art Gallery Theorem, the argument presented yields that if an art gallery has exactly <i>n</i> corners and at least one of every <span>\\(k + 2\\)</span> consecutive corners must be visible to at least one guard, then the number of guards needed is at most <span>\\(n/(k+4)\\)</span>. We also prove that <span>\\(\\gamma (G) \\le \\frac{n - n_2}{2}\\)</span> unless <span>\\(n = 2n_2\\)</span>, <span>\\(n_2\\)</span> is odd, and <span>\\(\\gamma (G) = \\frac{n - n_2 + 1}{2}\\)</span>. Together with the inequality <span>\\(\\gamma (G) \\le \\frac{n+n_2}{4}\\)</span>, obtained by Campos and Wakabayashi and independently by Tokunaga, this improves Chvátal’s bound. 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引用次数: 7

摘要

得到了极大外平面图(mops)的几个控制结果。经典控制问题是最小化n-顶点图G的顶点集S的大小,使得通过删除S的闭邻域得到的图\(G-n[S]\)不包含顶点。在Art Gallery定理的证明中,Chvátal表明,如果G是mop,则称为G的支配数并用\(\gamma(G)\)表示的最小尺寸至多为n/3。这里我们考虑一个修改,允许\(G-N[S]\)具有最多k的最大度。设\(\iota_k(G)\)表示实现这一点的最小集S的大小。如果\(n\le 2k+3\),则平凡地\(\iota _k(G)\le 1\)。设G是\(n\ge\max\{5,2k+3\}\)个顶点上的mop,其中\(n2\)的阶为2。已经为\(k=0\)和\(k=1\)获得了\(\iota_k(G)\)的上界,即\(\iota_{0}(G)\le\min\{\frac{n}{4}、\frac{n+n2}{5}、\ frac{n-n2}{3}\)和\。我们证明了对于任何\(k\ge0\),\(\iota_{k}(G)\le\min\{\frac{n}{k+4},\ frac{n+n2}{k+5},\frac{n-n2}{k+2}\}\)。对于美术馆定理的原始设置,所提出的论点得出,如果美术馆正好有n个角,并且每个\(k+2\)个连续角中至少有一个角必须对至少一个警卫可见,那么所需的警卫数量最多为\(n/(k+4)\)。我们还证明了\(\gamma(G)\le\frac{n-n2}{2}\),除非\(n=2n_2\),\(n2\)是奇数,并且\(\gamma(G)=\frac{n-n2+1}{2}\)。与Campos和Wakabayashi以及Tokunaga独立获得的不等式\(\gamma(G)\le\frac{n+n2}{4}\)一起,这改进了Chvátal的界。边界很陡。
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Extensions of the Art Gallery Theorem

Several domination results have been obtained for maximal outerplanar graphs (mops). The classical domination problem is to minimize the size of a set S of vertices of an n-vertex graph G such that \(G - N[S]\), the graph obtained by deleting the closed neighborhood of S, contains no vertices. In the proof of the Art Gallery Theorem, Chvátal showed that the minimum size, called the domination number of G and denoted by \(\gamma (G)\), is at most n/3 if G is a mop. Here we consider a modification by allowing \(G - N[S]\) to have a maximum degree of at most k. Let \(\iota _k(G)\) denote the size of a smallest set S for which this is achieved. If \(n \le 2k+3\), then trivially \(\iota _k(G) \le 1\). Let G be a mop on \(n \ge \max \{5,2k+3\}\) vertices, \(n_2\) of which are of degree 2. Upper bounds on \(\iota _k(G)\) have been obtained for \(k = 0\) and \(k = 1\), namely \(\iota _{0}(G) \le \min \{\frac{n}{4},\frac{n+n_2}{5},\frac{n-n_2}{3}\}\) and \(\iota _1(G) \le \min \{\frac{n}{5},\frac{n+n_2}{6},\frac{n-n_2}{3}\}\). We prove that \(\iota _{k}(G) \le \min \{\frac{n}{k+4},\frac{n+n_2}{k+5},\frac{n-n_2}{k+2}\}\) for any \(k \ge 0\). For the original setting of the Art Gallery Theorem, the argument presented yields that if an art gallery has exactly n corners and at least one of every \(k + 2\) consecutive corners must be visible to at least one guard, then the number of guards needed is at most \(n/(k+4)\). We also prove that \(\gamma (G) \le \frac{n - n_2}{2}\) unless \(n = 2n_2\), \(n_2\) is odd, and \(\gamma (G) = \frac{n - n_2 + 1}{2}\). Together with the inequality \(\gamma (G) \le \frac{n+n_2}{4}\), obtained by Campos and Wakabayashi and independently by Tokunaga, this improves Chvátal’s bound. The bounds are sharp.

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