两组连续平方和的方程

P. Bush, K. V. Murphy
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引用次数: 0

摘要

本文研究了具有连续平方整数和的方程,如$3^2 + 4^2 = 5^2$和$108^2 + 109^2 + 110^2 = 133^2 + 134^2$。一般来说,对于$m+1$连续平方整数的和,$x^2 +(x+1)^2 + \cdots +(x+m)^2$,存在一个不同的$m$连续平方的集合,$(x+n)^2 +(x+(n+1))^2 + \cdots +(x+(n+(m-1)))^2$,它们是相等的。我们提出了一种构造这些方程的自举方法,它产生了包含无限二维数组的解。我们应用类似的方法来构造连续的平方和方程,左边有$m+2$项,右边有$m$项,由两个不同的连续正方形组成,在等号左边分开一项,例如$2^2 + 3^2 + 6^2 = 7^2$。
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Equations of two sets of consecutive square sums
In this paper we investigate equations featuring sums of consecutive square integers, such as $3^2 + 4^2 = 5^2$, and $108^2 + 109^2 + 110^2 = 133^2 + 134^2$. In general, for a sum of $m+1$ consecutive square integers, $x^2 + (x+1)^2 + \cdots + (x+m)^2$, there is a distinct set of $m$ consecutive squares, $(x+n)^2 + (x+(n+1))^2 + \cdots + (x+(n+(m-1)))^2$, to which these are equal. We present a bootstrap method for constructing these equations, which yields solutions comprising an infinite two-dimensional array. We apply a similar method to constructing consecutive square sum equations involving $m+2$ terms on the left, and $m$ terms on the right, formed from two distinct sets of consecutive squares separated one term to the left of the equals sign, such as $2^2 + 3^2 + 6^2 = 7^2$.
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