求多项式系数线性递推定和解的阶乘基方法

Pub Date : 2023-07-01 DOI:10.1016/j.jsc.2022.11.002
Antonio Jiménez-Pastor , Marko Petkovšek
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引用次数: 0

摘要

具有多项式系数的线性递推Ly=0的非零解的求解问题,其中y具有定超几何和的形式,与Chen和Kauers(2017,Sec.8)的反向创造性伸缩问题有关,现在已经开放了三十年。这里我们提出了一个算法(在SageMath包中实现),它给定这样的递推和特征为零的域k上多项式空间k[n]的准三角、移位兼容的阶乘基B=〈Pk(n)〉k=0∞,计算解yn=∑k=0∞ckPk(n)的系数序列c=〈ck〉k=0∞所满足的递推(其中,由于B的拟三角性,右边的和对于每个n∈n终止)。更一般地说,如果B对一些m∈N是m筛的,我们的算法计算一个由系数序列c的m个部分满足的m个递归系统。如果可以找到这个系统的显式非零解,我们得到Ly=0的显式不零解。
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The factorial-basis method for finding definite-sum solutions of linear recurrences with polynomial coefficients

The problem of finding a nonzero solution of a linear recurrence Ly=0 with polynomial coefficients where y has the form of a definite hypergeometric sum, related to the Inverse Creative Telescoping Problem of Chen and Kauers (2017, Sec. 8), has now been open for three decades. Here we present an algorithm (implemented in a SageMath package) which, given such a recurrence and a quasi-triangular, shift-compatible factorial basis B=Pk(n)k=0 of the polynomial space K[n] over a field K of characteristic zero, computes a recurrence satisfied by the coefficient sequence c=ckk=0 of the solution yn=k=0ckPk(n) (where, thanks to the quasi-triangularity of B, the sum on the right terminates for each nN). More generally, if B is m-sieved for some mN, our algorithm computes a system of m recurrences satisfied by the m-sections of the coefficient sequence c. If an explicit nonzero solution of this system can be found, we obtain an explicit nonzero solution of Ly=0.

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