关于代数解结数

IF 1.1 Q1 MATHEMATICS Transactions of the London Mathematical Society Pub Date : 2013-08-28 DOI:10.1112/tlms/tlu004
Maciej Borodzik, Stefan Friedl
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引用次数: 12

摘要

结点K的代数解结数ua(K)是由村上仁提出的。它等于把K变成亚历山大多项式一节所需的最小交叉变化数。在之前的文章中,作者利用结点K的Blanchfield形式定义了一个不变量n(K),并证明了n(K)≥ua(K)。他们还证明了n(K)包含了(代数)解结数的所有以前的经典下界。本文证明了n(K)=ua(K)。
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On the algebraic unknotting number
The algebraic unknotting number ua(K) of a knot K was introduced by Hitoshi Murakami. It equals the minimal number of crossing changes needed to turn K into an Alexander polynomial one knot. In a previous paper, the authors used the Blanchfield form of a knot K to define an invariant n(K) and proved that n(K)⩽ua(K) . They also showed that n(K) subsumes all previous classical lower bounds on the (algebraic) unknotting number. In this paper, we prove that n(K)=ua(K) .
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来源期刊
CiteScore
1.40
自引率
0.00%
发文量
8
审稿时长
41 weeks
期刊最新文献
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