多项式导数的零自由区域

IF 1 Q1 MATHEMATICS Kragujevac Journal of Mathematics Pub Date : 2023-01-01 DOI:10.46793/kgjmat2303.403m
Mohammad Hedayetullah Mir, I. Nazir, I. A. Wani
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引用次数: 1

摘要

. set of polynomials》让P n denote表格P (z) = z(−a) k = 1 Y m n−−z z (k)里,用| a | k≤1和z | |≥1为≤k≤n−m . polynomials》为P (z) = z表格Q n−1 k = k(−z z z)里,用| k |≥1,哪里≤k≤n−1,布朗[2]stated《百康斯坦”问题找到C n P 0 (z)确实如此,那不是其为消失在| z | < C n”。他还把它和C = 1的纸放在同一个纸上。这个问题已经解决了,阿齐兹和扎格[1]。在这篇文章中,我们向阿齐兹和扎格尔的继任者报告了结果。
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On Zero Free Regions for Derivatives of a Polynomial
. Let P n denote the set of polynomials of the form p ( z ) = ( z − a ) m n − m Y k =1 ( z − z k ) , with | a | ≤ 1 and | z k | ≥ 1 for 1 ≤ k ≤ n − m. For the polynomials of the form p ( z ) = z Q n − 1 k =1 ( z − z k ) , with | z k | ≥ 1, where 1 ≤ k ≤ n − 1, Brown [2] stated the problem “Find the best constant C n such that p 0 ( z ) does not vanish in | z | < C n ”. He also conjectured in the same paper that C n = 1 n . This problem was solved by Aziz and Zarger [1]. In this paper, we obtain the results which generalizes the results of Aziz and Zarger.
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