VSLI布局的面积最大边长度权衡

Q4 Mathematics 信息与控制 Pub Date : 1985-07-01 DOI:10.1016/S0019-9958(85)80011-5
Norbert Blum
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引用次数: 4

摘要

我们构造了一个N节点图G,它具有(i)面积为O(N),最大边长为O(N1/2)的布局,(ii)面积为O(N5/4),最大边长为O(N1/4)的布局。我们证明了当1≤f(N)≤(O(N1/8)时,对于面积为Nf(N)的G,任何布局都有一条长度为Ω(N1/2/f(N)·log N)的边,因此G不存在两个度量都最优的布局。
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An area-maximum edge length trade-off for VSLI layout

We construct an N-node graph G which has (i) a layout with area O(N) and maximum edge length O(N1/2), (ii) a layout with area O(N5/4) and maximum edge length O(N1/4). We prove for 1 ≤ f(N) ≤ (O(N1/8) that any layout for G with area Nf(N) has an edge of length Ω(N1/2/f(N)·log N). Hence G has no layout which is optimal with respect to both measures.

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来源期刊
信息与控制
信息与控制 Mathematics-Control and Optimization
CiteScore
1.50
自引率
0.00%
发文量
4623
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