带换号系数的二阶差分方程

C. Fonseca, Can Kızılateş, Nazlıhan Terzio˘glu
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引用次数: 2

摘要

我们为序列(xn;k)的项提供了一个显式解:xn;k = xn􀀀1;k􀀀(􀀀1)b(n􀀀2)=kcxn􀀀2;k;对于n > 3,设x1;k = 1, x2;k = 0。考虑了几个特殊的例子。
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A second-order difference equation with sign-alternating coefficients
We provide an explicit solution for the terms of the sequence (xn;k) defined by xn;k = xn􀀀1;k 􀀀 (􀀀1)b(n􀀀2)=kcxn􀀀2;k ; for n > 3, setting x1;k = 1 and x2;k = 0. Several particular examples are considered.
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来源期刊
Kuwait Journal of Science & Engineering
Kuwait Journal of Science & Engineering MULTIDISCIPLINARY SCIENCES-
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审稿时长
3 months
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