关于gasch兹补定理的逆

Pub Date : 2023-03-01 DOI:10.1515/jgth-2022-0178
Benjamin Sambale
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引用次数: 3

摘要

摘要设无穷大群𝐺的正规子群。设N≤H≤G N \leq H \leq G使得在𝐻中存在一个补元并且(| N |, | G:H |)=1 (\lvert N \rvert, \lvert G:H \rvert)=1。如果抛掷是阿贝尔的,则抛掷的一个定理断言抛掷在𝐺中也有一个补。Brandis问过,是否可以用一些较弱的性质来代替二进制运算的交换性。证明了当所有的Sylow子群都是阿贝时,在𝐺中存在一个互补。另一方面,我们构造了Z≠(N)∩N '≠1 \mathrm{Z} (N) \cap N^ {\prime}\neq 1的反例。对于亚元群,条件Z≠(N)∩N ' =1 \mathrm{Z} (N) \cap N^ {\prime} =1暗示了补的存在性。最后,如果操作端是完美且无中心的,那么对于操作端,当且仅当Inn (N) \mathrm{Inn} (N)在Aut (N) \mathrm{Aut} (N)中有补时,gasch兹定理成立。
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On the converse of Gaschütz’ complement theorem
Abstract Let 𝑁 be a normal subgroup of a finite group 𝐺. Let N ≤ H ≤ G N\leq H\leq G such that 𝑁 has a complement in 𝐻 and ( | N | , | G : H | ) = 1 (\lvert N\rvert,\lvert G:H\rvert)=1 . If 𝑁 is abelian, a theorem of Gaschütz asserts that 𝑁 has a complement in 𝐺 as well. Brandis has asked whether the commutativity of 𝑁 can be replaced by some weaker property. We prove that 𝑁 has a complement in 𝐺 whenever all Sylow subgroups of 𝑁 are abelian. On the other hand, we construct counterexamples if Z ⁢ ( N ) ∩ N ′ ≠ 1 \mathrm{Z}(N)\cap N^{\prime}\neq 1 . For metabelian groups 𝑁, the condition Z ⁢ ( N ) ∩ N ′ = 1 \mathrm{Z}(N)\cap N^{\prime}=1 implies the existence of complements. Finally, if 𝑁 is perfect and centerless, then Gaschütz’ theorem holds for 𝑁 if and only if Inn ⁢ ( N ) \mathrm{Inn}(N) has a complement in Aut ⁢ ( N ) \mathrm{Aut}(N) .
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