阿基米德镶嵌中非并发最长路径图的最优嵌入

M. Nadeem, Ayesha Shabbir, Muhammad Imran
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引用次数: 0

摘要

最优图嵌入以保留原始图的结构和属性的方式表示低维空间中的图。这些技术在机器学习、数据挖掘和网络分析等领域有着广泛的应用。我们是否有一个小的(如果可能的话)k连通图,并且对于任意j个顶点,都有一条最长的路径可以避开所有顶点?Zamfirescu(1972)的问题是Gallai(1966)问题的第一个变体:连通图中所有最长的路径是否都有一个共同的顶点?有几个很好的例子可以回答Zamfirescu的问题。2001年,他要求根据这一性质研究几何格族。2017年,Chang和Yuan在阿基米德瓷砖中证明了这种图的存在。在这里,我们通过构造足够小阶的图来证明Chang和Yuan给出的图不是最优的。在阿基米德镶嵌中寻找非并发最长路径的问题是指在晶格中寻找路径,使路径不重叠或彼此相交,并且尽可能长。嵌入图的复杂度仍然是未知的。这个问题可能具有挑战性,因为它需要找到既长又不相交的路径,由于晶格结构的限制,这可能很困难。
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Optimal Embedding of Graphs with Nonconcurrent Longest Paths in Archimedean Tessellations
Optimal graph embeddings represent graphs in a lower dimensional space in a way that preserves the structure and properties of the original graph. These techniques have wide applications in fields such as machine learning, data mining, and network analysis. Do we have small (if possible minimal) k -connected graphs with the property that for any j vertices there is a longest path avoiding all of them? This question of Zamfirescu (1972) was the first variant of Gallai’s question (1966): Do all longest paths in a connected graph share a common vertex? Several good examples answering Zamfirescu’s question are known. In 2001, he asked to investigate the family of geometrical lattices with respect to this property. In 2017, Chang and Yuan proved the existence of such graphs in Archimedean tiling. Here, we prove that the graphs presented by Chang and Yuan are not optimal by constructing such graphs of sufficiently smaller orders. The problem of finding nonconcurrent longest paths in Archimedean tessellations refers to finding paths in a lattice such that the paths do not overlap or intersect with each other and are as long as possible. The complexity of embedding graph is still unknown. This problem can be challenging because it requires finding paths that are both long and do not intersect, which can be difficult due to the constraints of the lattice structure.
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