{"title":"具有一阶导数依赖的半线上奇异三阶bvp的正解","authors":"Abdelhamid Benmezaï, El-Djouher Sedkaoui","doi":"10.2478/ausm-2021-0006","DOIUrl":null,"url":null,"abstract":"Abstract In this paper, we investigate the existence of a positive solution to the third-order boundary value problem { -u‴(t)+k2u′(t)=φ(t)f(t,u(t),u′(t)), t>0u(0)=u′(0)=u′(+∞)=0, \\left\\{ \\matrix{- u'''\\left( t \\right) + {k^2}u'\\left( t \\right) = \\phi \\left( t \\right)f\\left( {t,u\\left( t \\right),u'\\left( t \\right)} \\right),\\,\\,\\,t > 0 \\hfill \\cr u\\left( 0 \\right) = u'\\left( 0 \\right) = u'\\left( { + \\infty } \\right) = 0, \\hfill \\cr} \\right. where k is a positive constant, ϕ ∈ L1 (0;+ ∞) is nonnegative and does vanish identically on (0;+ ∞) and the function f : ℝ+ × (0;+ ∞) × (0;+ ∞) → ℝ+ is continuous and may be singular at the space variable and at its derivative.","PeriodicalId":0,"journal":{"name":"","volume":null,"pages":null},"PeriodicalIF":0.0,"publicationDate":"2021-08-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"1","resultStr":"{\"title\":\"Positive solution for singular third-order BVPs on the half line with first-order derivative dependence\",\"authors\":\"Abdelhamid Benmezaï, El-Djouher Sedkaoui\",\"doi\":\"10.2478/ausm-2021-0006\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"Abstract In this paper, we investigate the existence of a positive solution to the third-order boundary value problem { -u‴(t)+k2u′(t)=φ(t)f(t,u(t),u′(t)), t>0u(0)=u′(0)=u′(+∞)=0, \\\\left\\\\{ \\\\matrix{- u'''\\\\left( t \\\\right) + {k^2}u'\\\\left( t \\\\right) = \\\\phi \\\\left( t \\\\right)f\\\\left( {t,u\\\\left( t \\\\right),u'\\\\left( t \\\\right)} \\\\right),\\\\,\\\\,\\\\,t > 0 \\\\hfill \\\\cr u\\\\left( 0 \\\\right) = u'\\\\left( 0 \\\\right) = u'\\\\left( { + \\\\infty } \\\\right) = 0, \\\\hfill \\\\cr} \\\\right. where k is a positive constant, ϕ ∈ L1 (0;+ ∞) is nonnegative and does vanish identically on (0;+ ∞) and the function f : ℝ+ × (0;+ ∞) × (0;+ ∞) → ℝ+ is continuous and may be singular at the space variable and at its derivative.\",\"PeriodicalId\":0,\"journal\":{\"name\":\"\",\"volume\":null,\"pages\":null},\"PeriodicalIF\":0.0,\"publicationDate\":\"2021-08-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"1\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.2478/ausm-2021-0006\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.2478/ausm-2021-0006","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
Positive solution for singular third-order BVPs on the half line with first-order derivative dependence
Abstract In this paper, we investigate the existence of a positive solution to the third-order boundary value problem { -u‴(t)+k2u′(t)=φ(t)f(t,u(t),u′(t)), t>0u(0)=u′(0)=u′(+∞)=0, \left\{ \matrix{- u'''\left( t \right) + {k^2}u'\left( t \right) = \phi \left( t \right)f\left( {t,u\left( t \right),u'\left( t \right)} \right),\,\,\,t > 0 \hfill \cr u\left( 0 \right) = u'\left( 0 \right) = u'\left( { + \infty } \right) = 0, \hfill \cr} \right. where k is a positive constant, ϕ ∈ L1 (0;+ ∞) is nonnegative and does vanish identically on (0;+ ∞) and the function f : ℝ+ × (0;+ ∞) × (0;+ ∞) → ℝ+ is continuous and may be singular at the space variable and at its derivative.