任意簇大小的1均值和1中位数2聚类问题:复杂性和近似

Q3 Decision Sciences Yugoslav Journal of Operations Research Pub Date : 2022-01-01 DOI:10.2298/yjor211018008p
A. Pyatkin
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引用次数: 1

摘要

我们考虑下面的2聚类问题。给定欧几里德空间中的N个点,将其划分为两个子集(聚类),使聚类元素与其中心之间的距离平方和最小。第一个聚类的中心与其质心(均值)重合,而第二个聚类的中心应从初始点(中间点)的集合中选择。众所周知,如果将集群的基数作为输入的一部分给出,则该问题是np困难的。在本文中,我们证明了在任意簇大小的情况下问题仍然是np困难的,并提出了一个2逼近多项式时间算法来解决这个问题。
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1-mean and 1-medoid 2-clustering problem with arbitrary cluster sizes: Complexity and approximation
We consider the following 2-clustering problem. Given N points in Euclidean space, partition it into two subsets (clusters) so that the sum of squared distances between the elements of the clusters and their centers would be minimum. The center of the first cluster coincides with its centroid (mean) while the center of the second cluster should be chosen from the set of the initial points (medoid). It is known that this problem is NP-hard if the cardinalities of the clusters are given as a part of the input. In this paper we prove that the problem remains NP-hard in the case of arbitrary clusters sizes and suggest a 2-approximation polynomial-time algorithm for this problem.
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来源期刊
Yugoslav Journal of Operations Research
Yugoslav Journal of Operations Research Decision Sciences-Management Science and Operations Research
CiteScore
2.50
自引率
0.00%
发文量
14
审稿时长
24 weeks
期刊最新文献
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