针对一个敏捷且可见的逃犯的混合搜索游戏是单调的

Guillaume Mescoff, C. Paul, D. Thilikos
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引用次数: 1

摘要

我们考虑混合搜索游戏对抗一个敏捷且可见的逃犯。这是经典逃亡搜索游戏在图形上的变体,搜索者可以被放置在(或从)顶点或沿着边缘滑动。此外,逃亡者位于图的边缘,可以随时沿着无人看守的路径移动。对图形$G$的一个灵活且可见的逃亡者的混合搜索数,表示为$avms(G)$,是在此图搜索变体中捕获逃亡者所需的最小搜索者数。我们的主要结果是,这个图搜索变体是单调的,因为如果我们将搜索策略限制为那些不允许逃犯访问已经干净的边缘的搜索策略,则成功搜索策略所需的搜索者数量不会增加。这意味着针对敏捷和可见逃犯的混合搜索策略可以被多项式地证明,因此,给定一个图$G$和一个整数$k,$,决定$avms(G)\leq k$是否在NP中的问题。我们的证明是基于紧荆棘概念的引入,紧荆棘作为相应搜索参数的障碍。我们的结果表明,对于一个图$G$, $avms(G)$等于$G$的笛卡尔树积数,这是最小的$k$,其中$G$是树和团在$k$顶点上的笛卡尔积的次项。
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The mixed search game against an agile and visible fugitive is monotone
We consider the mixed search game against an agile and visible fugitive. This is the variant of the classic fugitive search game on graphs where searchers may be placed to (or removed from) the vertices or slide along edges. Moreover, the fugitive resides on the edges of the graph and can move at any time along unguarded paths. The mixed search number against an agile and visible fugitive of a graph $G$, denoted $avms(G)$, is the minimum number of searchers required to capture to fugitive in this graph searching variant. Our main result is that this graph searching variant is monotone in the sense that the number of searchers required for a successful search strategy does not increase if we restrict the search strategies to those that do not permit the fugitive to visit an already clean edge. This means that mixed search strategies against an agile and visible fugitive can be polynomially certified, and therefore that the problem of deciding, given a graph $G$ and an integer $k,$ whether $avms(G)\leq k$ is in NP. Our proof is based on the introduction of the notion of tight bramble, that serves as an obstruction for the corresponding search parameter. Our results imply that for a graph $G$, $avms(G)$ is equal to the Cartesian tree product number of $G$ that is the minimum $k$ for which $G$ is a minor of the Cartesian product of a tree and a clique on $k$ vertices.
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