关于平方的可加补的格林问题

Pub Date : 2020-12-03 DOI:10.5802/crmath.107
Yuchen Ding
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引用次数: 2

摘要

设A和B是非负整数的两个子集。如果所有足够大的整数n都可以写成A + B,其中A∈A, B∈B,我们称A和B为可加补数。设S ={12,22,32,···}为所有平方数的集合。Ben Green对s的加性补很感兴趣,他问是否存在一个B = {bn}n=1的可加性补,满足bn = π 2 16 n2 +o(n2)。最近,Chen和Fang证明了如果B是这样的可加补,则limsup n→∞π2 16 n 2−bn n /2 logn≥√2 π 1 log4。他们进一步推测limsup n→∞π2 16 n 2 - bn n /2 logn =+∞。在本文中,我们给出了一个更强的结果,即limsup n→∞π2 16 n 2−bn n≥π 4,从而证实了这个猜想。2020数学学科分类。11B13, 11B75。2020年8月3日收稿,2020年8月19日改稿,2020年8月20日收稿。
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Green’s problem on additive complements of the squares
Let A and B be two subsets of the nonnegative integers. We call A and B additive complements if all sufficiently large integers n can be written as a +b, where a ∈ A and b ∈ B . Let S = {12,22,32, · · ·} be the set of all square numbers. Ben Green was interested in the additive complement of S. He asked whether there is an additive complement B = {bn }n=1 ⊆Nwhich satisfies bn = π 2 16 n 2+o(n2). Recently, Chen and Fang proved that if B is such an additive complement, then limsup n→∞ π2 16 n 2 −bn n1/2 logn ≥ √ 2 π 1 log4 . They further conjectured that limsup n→∞ π2 16 n 2 −bn n1/2 logn =+∞. In this paper, we confirm this conjecture by giving a much more stronger result, i.e., limsup n→∞ π2 16 n 2 −bn n ≥ π 4 . 2020 Mathematics Subject Classification. 11B13, 11B75. Manuscript received 3rd August 2020, revised 19th August 2020, accepted 20th August 2020.
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