{"title":"进一步等价二项式和","authors":"M. Bai, W. Chu","doi":"10.5802/CRMATH.184","DOIUrl":null,"url":null,"abstract":"Five binomial sums are extended by a free parameter m, that are shown, through the generating function method, to have the same value. These sums generalize the ones by Ruehr (1980), who discovered them in the study of two unexpected equalities between definite integrals. 2020 Mathematics Subject Classification. 11B65, 05A10. Manuscript received 22nd December 2020, revised and accepted 2nd February 2021. In 1980, Kimura [14] proposed a monthly problem about two curious identities of definite integrals. If f is continuous on [− 1 2 , 3 2 ], then for δ= 0, 1, prove that ∫ 3 2 − 2 x f ( 3x −2x3)dx = 2∫ 1 0 x f ( 3x −2x3)dx. In his (trigonometric) proof, Ruehr [14] observed by linearity that to prove these identities, it is enough to verify them for monomials f (x) = xn . This led him to discover the following interesting identities An =Cn and Bn = Dn , where for a natural number n, the four binomial sums are defined by An = n ∑ j=0 3 j ( 3n − j 2n ) , Bn = n ∑ j=0 2 j ( 3n +1 2n + j +1 ) , Cn = 2n ∑ j=0 (−3) j ( 3n − j n ) , Dn = 2n ∑ j=0 (−4) j ( 3n +1 n + j +1 ) . ∗Corresponding author. ISSN (electronic) : 1778-3569 https://comptes-rendus.academie-sciences.fr/mathematique/ 422 Mei Bai and Wenchang Chu Allouche [1, 2] examined the related integrals and reviewed these identities in a more elegant manner. These identities were also reconfirmed by Meehan et al [16] who found, through the WZ-algorithm, that these four sequences satisfy also the common recurrence relation: X0 = 1 and Xn+1 = 27 4 Xn − 3 (3n+1 n ) 4(n +1) . By introducing a variable, Alzer and Prodinger [3] recently considered the polynomial analogues, that were also examined by Kilic–Arikan [13] through bijections. By applying the generating function approach to the binomial convolutions Ωn = n ∑ k=0 ( 3k k )( 3n −3k n −k ) the authors [4] not only confirmed the identities Ωn = An = Bn =Cn = Dn ; (1) but also found the two additional ones Ωn = En = Fn , (2)","PeriodicalId":10620,"journal":{"name":"Comptes Rendus Mathematique","volume":"80 1","pages":"421-425"},"PeriodicalIF":0.8000,"publicationDate":"2021-05-27","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Further Equivalent Binomial Sums\",\"authors\":\"M. Bai, W. Chu\",\"doi\":\"10.5802/CRMATH.184\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"Five binomial sums are extended by a free parameter m, that are shown, through the generating function method, to have the same value. These sums generalize the ones by Ruehr (1980), who discovered them in the study of two unexpected equalities between definite integrals. 2020 Mathematics Subject Classification. 11B65, 05A10. Manuscript received 22nd December 2020, revised and accepted 2nd February 2021. In 1980, Kimura [14] proposed a monthly problem about two curious identities of definite integrals. If f is continuous on [− 1 2 , 3 2 ], then for δ= 0, 1, prove that ∫ 3 2 − 2 x f ( 3x −2x3)dx = 2∫ 1 0 x f ( 3x −2x3)dx. In his (trigonometric) proof, Ruehr [14] observed by linearity that to prove these identities, it is enough to verify them for monomials f (x) = xn . This led him to discover the following interesting identities An =Cn and Bn = Dn , where for a natural number n, the four binomial sums are defined by An = n ∑ j=0 3 j ( 3n − j 2n ) , Bn = n ∑ j=0 2 j ( 3n +1 2n + j +1 ) , Cn = 2n ∑ j=0 (−3) j ( 3n − j n ) , Dn = 2n ∑ j=0 (−4) j ( 3n +1 n + j +1 ) . ∗Corresponding author. 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引用次数: 0
摘要
五个二项式和由一个自由参数m展开,通过生成函数法显示出它们具有相同的值。这些和推广了Ruehr(1980)的和,Ruehr在研究定积分之间的两个意想不到的等式时发现了它们。2020数学学科分类[j] . 11B65, 05A10。稿件于2020年12月22日收稿,2021年2月2日修订并接受。1980年,Kimura[14]提出了关于两个奇异的定积分恒等式的月问题。如果f在[- 1,2,3,2]上连续,那么对于δ= 0,1,证明∫32 - 2x f (3x - 2x3)dx = 2∫10 x f (3x - 2x3)dx。在他的(三角)证明中,Ruehr[14]通过线性观察到,为了证明这些恒等式,只要对单项式f (x) = xn进行验证就足够了。这使他发现以下有趣的身份= Cn和Bn = Dn,为自然数n,定义的四个二项金额= n∑j = 0 3 (3 n−j 2 n) Bn n =∑j = 0 2 (3 n + 1 2 n + j + 1), Cn = 2 n∑j = 0(−3)(3 n−j n), Dn = 2 n∑j = 0(−4)(3 n + 1 n + j + 1)。∗通讯作者。422白梅、楚文昌[1,2]考察了相关的积分,更优雅地回顾了这些恒等式。Meehan等人[16]也再次证实了这些等式,他们通过wz算法发现这四个序列也满足共同递归关系:X0 = 1和Xn+1 = 274 Xn−3 (3n+1 n) 4(n +1)。通过引入一个变量,Alzer和Prodinger[3]最近考虑了多项式类似物,Kilic-Arikan[13]也通过双射检验了多项式类似物。将生成函数方法应用于二项式卷积Ωn = n∑k=0 (3k k)(3n−3k n−k),作者[4]不仅证实了等式Ωn = An = Bn =Cn = Dn;(1)还发现了另外两个Ωn = En = Fn, (2)
Five binomial sums are extended by a free parameter m, that are shown, through the generating function method, to have the same value. These sums generalize the ones by Ruehr (1980), who discovered them in the study of two unexpected equalities between definite integrals. 2020 Mathematics Subject Classification. 11B65, 05A10. Manuscript received 22nd December 2020, revised and accepted 2nd February 2021. In 1980, Kimura [14] proposed a monthly problem about two curious identities of definite integrals. If f is continuous on [− 1 2 , 3 2 ], then for δ= 0, 1, prove that ∫ 3 2 − 2 x f ( 3x −2x3)dx = 2∫ 1 0 x f ( 3x −2x3)dx. In his (trigonometric) proof, Ruehr [14] observed by linearity that to prove these identities, it is enough to verify them for monomials f (x) = xn . This led him to discover the following interesting identities An =Cn and Bn = Dn , where for a natural number n, the four binomial sums are defined by An = n ∑ j=0 3 j ( 3n − j 2n ) , Bn = n ∑ j=0 2 j ( 3n +1 2n + j +1 ) , Cn = 2n ∑ j=0 (−3) j ( 3n − j n ) , Dn = 2n ∑ j=0 (−4) j ( 3n +1 n + j +1 ) . ∗Corresponding author. ISSN (electronic) : 1778-3569 https://comptes-rendus.academie-sciences.fr/mathematique/ 422 Mei Bai and Wenchang Chu Allouche [1, 2] examined the related integrals and reviewed these identities in a more elegant manner. These identities were also reconfirmed by Meehan et al [16] who found, through the WZ-algorithm, that these four sequences satisfy also the common recurrence relation: X0 = 1 and Xn+1 = 27 4 Xn − 3 (3n+1 n ) 4(n +1) . By introducing a variable, Alzer and Prodinger [3] recently considered the polynomial analogues, that were also examined by Kilic–Arikan [13] through bijections. By applying the generating function approach to the binomial convolutions Ωn = n ∑ k=0 ( 3k k )( 3n −3k n −k ) the authors [4] not only confirmed the identities Ωn = An = Bn =Cn = Dn ; (1) but also found the two additional ones Ωn = En = Fn , (2)
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