A Bayesian Examines the Lady Tasting Tea

P. E. Pfeifer
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Abstract

This technical note accompanies the case/class on “The Lady Tasting Tea” (LTT). It describes how a Bayesian would update his or her prior probability for the probability the LTT can correctly distinguish cups of tea based on whether the milk was added first or last. This long-form note describes both a discrete model (LTT has p of 0.5 or 0.8) and a more complicated continuous model (p is beta distributed). The abridged note (UVA-QA-0768) describes only the discrete model. The case/class itself provides a very useful analogy with which students can explore the elements of statistical inference. Excerpt UVA-QA-0769 Jun. 13, 2011 A Bayesian Examines the Lady Tasting Tea Before I describe what Bayesian statistics can add to the discussion of the lady tasting tea (LTT), let me remind you where the classical statisticians left us. They used the binomial distribution to calculate the probability distribution of the number the LTT gets correct (in 10 trials) under two scenarios. The first scenario, called the null hypothesis, is that she is guessing. Guessing would mean P, the probability that she correctly identifies which of two cups has had milk poured into it first and which had tea in it first, is 0.5. The second scenario, called the alternative hypothesis, is that she is skilled. To keep things from getting too complicated, we assume that skilled means P = 0.8 for each trial. The resulting probability distributions are given in Table 1. With these probabilities, the classical statistician can make probability statements about what will happen undereither scenario. Table 1. Probability distributions for number correct in 10 trials. . . .
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一个贝叶斯分析品茶的女士
本技术说明随“女士品茶”(LTT)案例/课程而附。它描述了贝叶斯如何更新他或她的先验概率,使LTT能够根据牛奶是先加还是后加正确区分茶的概率。这篇长篇笔记既描述了一个离散模型(LTT的p值为0.5或0.8),也描述了一个更复杂的连续模型(p为beta分布)。删节说明(UVA-QA-0768)只描述了离散模型。案例/课程本身提供了一个非常有用的类比,学生可以利用它来探索统计推断的要素。在我描述贝叶斯统计可以为女士品茶(LTT)的讨论添加什么之前,让我提醒你经典统计学家把我们放在哪里。他们使用二项分布来计算LTT在两种情况下(在10次试验中)正确次数的概率分布。第一种情况,称为零假设,即她在猜测。猜测意味着P,她正确识别出两个杯子中哪一个先倒了牛奶,哪一个先倒了茶的概率是0.5。第二种情况被称为备用假设,即她是熟练的。为了避免事情变得过于复杂,我们假设熟练意味着每次试验P = 0.8。得到的概率分布如表1所示。有了这些概率,经典统计学家就可以对两种情况下发生的事情做出概率陈述。表1。10次试验中正确数字的概率分布. . . .
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