Analysis of power loss in Ni-Cu-Zn ferrites

E. Otsuki, J. Kim
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引用次数: 1

Abstract

The power loss analysis was carried out for Ni-Cu-Zn ferrite samples with different content of NiO and ZnO. The power loss, Pc/spl nu/ decreases monotonically with increasing temperature and attains to a certain value at around 100/spl sim/120 degrees Celsius. The frequency dependence of Pc/spl nu/ can be explained by Pc/spl nu//spl sim/f, and n is independent of the frequency, f up to 1 MHz. The Pc/spl nu/ decreases with an increase in ZnO/NiO. The Pc/spl nu/ was separated to hysteresis loss, Ph and residual loss, (Pc/spl nu/-Ph). The temperature characteristics and compositional dependence of Pc/spl nu/ can be attributed to the Ph, while (Pc/spl nu/-Ph) is not affected by both temperature and ZnO/NiO. By analyzing temperature and composition dependence of Ph and initial permeability, u/sub i/ following equations could be formularized. u/sub i/u/sub 0/ = I/sub s//sup 2//(K/sub I/ + bs/sub 0/l/sub s/) (1), Wh = 13.5(I/sub s//sup 2//u/sub i/u/sub 0/) (2), where u/sub 0/ is permeability of vacuum, I/sub s/ saturation magnetization, K/sub I/ anisotropy constant, s/sub 0/ internal heterogeneous stress, l/sub s/ magnetostriction constant, b unknown constant. Wh hysteresis loss per one cycle of excitation (Ph = Wh*f). Steinmetz constant of Ni-Cu-Zn ferrites, m = 1.64/spl sim/2.2 is smaller than the one of Mn-Zn ferrites, which suggests the difference of loss mechanism between these materials.
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Ni-Cu-Zn铁氧体的功率损耗分析
对NiO和ZnO含量不同的Ni-Cu-Zn铁氧体样品进行了功率损耗分析。功率损耗Pc/spl nu/随温度升高而单调减小,在100/spl sim/120℃左右达到一定值。Pc/spl nu/的频率依赖性可以用Pc/spl nu//spl sim/f来解释,n与频率无关,f最高可达1 MHz。Pc/spl nu/随ZnO/NiO的增加而减小。将Pc/spl nu/分解为滞后损耗、Ph和残余损耗(Pc/spl nu/-Ph)。Pc/spl nu/的温度特性和组分依赖性主要受Ph的影响,而(Pc/spl nu/-Ph)不受温度和ZnO/NiO的影响。通过分析Ph值与初始渗透率对温度和组分的依赖关系,可以得到u/sub i/的公式。u/sub i/u/sub 0/ = i/ sub s//sup 2//(K/sub i/ + bs/sub 0/l/sub s/) (1), Wh = 13.5(i/ sub s//sup 2//u/sub i/u/sub 0/)(2),其中u/sub 0/为真空磁导率,i/ sub s/饱和磁化强度,K/sub i/各向异性常数,s/sub 0/内部非均质应力,l/sub s/磁致伸缩常数,b未知常数。每一个激励周期的迟滞损耗(Ph = Wh*f)。Ni-Cu-Zn铁氧体的Steinmetz常数m = 1.64/spl sim/2.2小于Mn-Zn铁氧体的Steinmetz常数,说明两者的损耗机理存在差异。
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