A Tangent Inequality Over Primes

Pub Date : 2023-11-28 DOI:10.1007/s11253-023-02245-z
S. I. Dimitrov
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引用次数: 0

Abstract

We introduce a new Diophantine inequality with prime numbers. Let \(1<c<\frac{10}{9}.\) We show that, for any fixed θ > 1, every sufficiently large positive number N, and a small constant ε > 0, the tangent inequality

$$\left|{p}_{1}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{1}\right)+{p}_{2}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{2}\right)+{p}_{3}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{3}\right)-N\right|<\varepsilon $$

has a solution in prime numbers p1, p2, and p3.

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质数上的正切不等式
我们引入了一个新的素数丢芬图不等式。让 \(1<c<\frac{10}{9}.\) 我们证明,对于任意固定的θ &gt;1、每一个足够大的正数N,以及一个小常数ε &gt;0, tan不等式$$\left|{p}_{1}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{1}\right)+{p}_{2}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{2}\right)+{p}_{3}^{c} {\mathrm{tan}}^{\theta }\left(\mathrm{log}{p}_{3}\right)-N\right|<\varepsilon $$有质数p1 p2 p3的解。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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