The number of real zeros of polynomials with constrained coefficients

Tamás Erdélyi
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Abstract

We use Jensen's formula to give an upper bound for the number of real zeros of polynomials with constrained coefficients. We prove that there is an absolute constant $c > 0$ such that every polynomial $P$ of the form $$P(z) = \sum_{j=0}^{n}{a_jz^j}\,, \quad |a_0| = 1\,, \quad |a_j| \leq M\,, \quad a_j \in \Bbb{C}\,, \quad M \geq 1\,,$$ has at most $cn^{1/2}(1+\log M)^{1/2}$ zeros in the interval $[-1,1]$. This result is sharp up to the multiplicative constant $c > 0$ and extends an earlier result of Borwein, Erd\'elyi, and K\'os from the case $M=1$ to the case $M \geq $1. This has also been proved recently with the factor $(1+\log M)$ rather than $(1+\log M)^{1/2}$ in the Appendix of a recent paper by Jacob and Nazarov by using a different method. We also prove that there is an absolute constant $c > 0$ such that every polynomial $P$ of the above form has at most $(c/a)(1+\log M)$ zeros in the interval $[-1+a,1-a]$ with $a \in (0,1)$. Finally we correct a somewhat incorrect proof of an earlier result of Borwein and Erd\'elyi by proving that there is a constant $\eta > 0$ such that every polynomial $P$ of the above form with $M = 1$ has at most $\eta n^{1/2}$ zeros inside any polygon with vertices on the unit circle, where the multiplicative constant $\eta > 0$ depends only on the polygon.
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系数受约束的多项式的实零点个数
我们利用詹森公式给出了具有约束系数的多项式的实零点个数的上限。我们证明存在一个绝对常数 $c > 0$,使得形式为 $$P(z) =\sum_{j=0}^{n}{a_jz^j}\, \quad |a_0| = 1\、, \quad |a_j| \leq M\,, \quad a_j\in \Bbb{C}\,, \quad M \geq 1\,, $$ 在区间 $[-1,1]$ 中最多有 $cn^{1/2}(1+\log M)^{1/2}$ 零点。这一结果在乘法常数 $c > 0$ 的范围内都是尖锐的,并将 Borwein, Erd\'elyi, and K\'os 早期的一个结果从 $M=1$ 的情况扩展到了 $M \geq $1 的情况。最近,雅各布和纳扎罗夫在其最新论文的附录中用不同的方法证明了这一结果,其因子为 $(1+\log M)$ 而不是 $(1+\log M)^{1/2}$ 。我们还证明了存在一个绝对常数 $c > 0$,使得上述形式的每个多项式 $P$ 在区间 $[-1+a,1-a]$ 中最多有$(c/a)(1+\log M)$ 的零点,其中$a 在 (0,1)$ 中。最后,我们纠正了 Borwein 和 Erd\'elyi 早先一个结果的不正确证明,证明存在一个常量 $\eta > 0$,使得上面形式的多项式 $P$ 在任何顶点在单位圆上的多边形内最多有 $\etan^{1/2}$ 的零点,其中乘法常量 $\eta > 0$ 只取决于多边形。
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