$Kite_{p+2,p}$ is determined by its Laplacian spectrum

IF 0.6 Q3 MATHEMATICS Transactions on Combinatorics Pub Date : 2021-09-01 DOI:10.22108/TOC.2021.126646.1798
H. Topcu
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引用次数: 0

Abstract

$Kite_{n,p}$ denotes the kite graph that is obtained by appending complete graph with order $pgeq4$ to an endpoint of path graph with order $n-p$‎. ‎It is shown that $Kite_{n,p}$ is determined by its adjacency spectrum for all $p$ and $n$ [H‎. ‎Topcu and ‎S‎. ‎Sorgun‎, ‎The kite graph is determined by its adjacency spectrum‎, ‎Applied Math‎. ‎and Comp.‎, ‎330 (2018) 134--142]‎. ‎For $n-p=1$‎, ‎it is proven that $Kite_{n,p}$ is determined by its signless Laplacian spectrum when $ngeq4$‎, ‎$nneq5$ and is also determined by its distance spectrum when $ngeq4$ [K‎. ‎C‎. ‎Das and ‎M‎. ‎Liu‎, ‎Kite graphs are determined by their spectra‎, ‎Applied Math‎. ‎and Comp.‎, ‎297 (2017) 74--78]‎. ‎In this note‎, ‎we say that $Kite_{n,p}$ is determined by its Laplacian spectrum for $n-pleq2$‎.
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$Kite_{p+2,p}$由其拉普拉斯谱确定
$Kite_{n.p}$表示通过将阶为$pgeq4-dollar的完全图附加到阶为$n-p的路径图的端点而获得的风筝图$结果表明,对于所有$p和$n$[H]-Topcu和S.Sorgun,$Kite_{n.p}$是由其相邻谱确定的。风筝图是由其邻近谱确定的,应用数学;以及Comp.,330°(2018)134-142]。当$n-p=1美元时,证明了$Kite_{n.p}$在$ngeq4$$nneq5$s时由其无符号拉普拉斯谱确定,在$angeq4$[K]时也由其距离谱确定;--Das和M;Liu,Kite图由其谱确定,应用数学;以及Comp.297×(2017)74-78]。在这个注释中,我们说$Kite_{n.p}$是由$n-pleq2$的拉普拉斯谱确定的。
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来源期刊
CiteScore
0.80
自引率
0.00%
发文量
2
审稿时长
30 weeks
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