The power set and the set of permutations with finitely many non-fixed points of a set

Pub Date : 2023-05-10 DOI:10.1002/malq.202100070
Guozhen Shen
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引用次数: 3

Abstract

For a cardinal  a $\mathfrak {a}$ , we write S fin ( a ) $\operatorname{\mathcal {S}_{\text{fin}}}(\mathfrak {a})$ for the cardinality of the set of permutations with finitely many non-fixed points of a set which is of cardinality  a $\mathfrak {a}$ . We investigate the relationships between 2 a $2^\mathfrak {a}$ and S fin ( a ) $\operatorname{\mathcal {S}_{\text{fin}}}(\mathfrak {a})$ for an arbitrary infinite cardinal  a $\mathfrak {a}$ in  ZF $\mathsf {ZF}$ (without the axiom of choice). It is proved in  ZF $\mathsf {ZF}$ that 2 a S fin ( a ) $2^\mathfrak {a}\ne \operatorname{\mathcal {S}_{\text{fin}}}(\mathfrak {a})$ for all infinite cardinals  a $\mathfrak {a}$ , and we show that this is the best possible result.

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幂集和集的具有有限多个不动点的置换集
对于基数$\mathfrak{a}$,我们写S fin(a)$\运算符名称{\mathcal{S}_{\text{fin}}(\mathfrak{a})$为基数为a$\mathfrak{a}$的集合的具有有限多个非不动点的置换集的基数。我们研究了2a$2^\mathfrak{a}$与S fin之间的关系(a)$\运算符名称{\mathcal{S}_{\text{fin}}(\mathfrak{a})$,用于ZF$\mathsf{ZF}$中的任意无限基数a$\mathfrak{a}$(没有选择公理)。在ZF$\mathsf{ZF}$中证明了2a≠S fin(a)$2^\mathfrak{a}\ ne \ operator name{\mathcal{S}_{\text{fin}}(\mathfrak{a})$对于所有无限基数a$\mathfrak{a}$,我们证明这是最好的可能结果。
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