Optimal Quantum Sample Complexity of Learning Algorithms

Srinivasan Arunachalam, R. D. Wolf
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引用次数: 86

Abstract

$ \newcommand{\eps}{\varepsilon} $In learning theory, the VC dimension of a concept class $C$ is the most common way to measure its "richness." In the PAC model $$ \Theta\Big(\frac{d}{\eps} + \frac{\log(1/\delta)}{\eps}\Big) $$ examples are necessary and sufficient for a learner to output, with probability $1-\delta$, a hypothesis $h$ that is $\eps$-close to the target concept $c$. In the related agnostic model, where the samples need not come from a $c\in C$, we know that $$ \Theta\Big(\frac{d}{\eps^2} + \frac{\log(1/\delta)}{\eps^2}\Big) $$ examples are necessary and sufficient to output an hypothesis $h\in C$ whose error is at most $\eps$ worse than the best concept in $C$. Here we analyze quantum sample complexity, where each example is a coherent quantum state. This model was introduced by Bshouty and Jackson, who showed that quantum examples are more powerful than classical examples in some fixed-distribution settings. However, Atici and Servedio, improved by Zhang, showed that in the PAC setting, quantum examples cannot be much more powerful: the required number of quantum examples is $$ \Omega\Big(\frac{d^{1-\eta}}{\eps} + d + \frac{\log(1/\delta)}{\eps}\Big)\mbox{ for all }\eta> 0. $$ Our main result is that quantum and classical sample complexity are in fact equal up to constant factors in both the PAC and agnostic models. We give two approaches. The first is a fairly simple information-theoretic argument that yields the above two classical bounds and yields the same bounds for quantum sample complexity up to a $\log(d/\eps)$ factor. We then give a second approach that avoids the log-factor loss, based on analyzing the behavior of the "Pretty Good Measurement" on the quantum state identification problems that correspond to learning. This shows classical and quantum sample complexity are equal up to constant factors.
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学习算法的最优量子样本复杂度
$ \newcommand{\eps}{\varepsilon} $在学习理论中,概念类$C$的VC维是衡量其“丰富度”的最常用方法。在PAC模型中$$ \Theta\Big(\frac{d}{\eps} + \frac{\log(1/\delta)}{\eps}\Big) $$示例对于学习者输出来说是必要和充分的,其概率为$1-\delta$,假设$h$是$\eps$ -接近目标概念$c$。在相关的不可知论模型中,样本不需要来自$c\in C$,我们知道$$ \Theta\Big(\frac{d}{\eps^2} + \frac{\log(1/\delta)}{\eps^2}\Big) $$示例是必要的,足以输出一个假设$h\in C$,其误差最多$\eps$比$C$中的最佳概念差。这里我们分析量子样本复杂度,其中每个例子都是相干量子态。这个模型是由Bshouty和Jackson提出的,他们表明,在一些固定分布的环境中,量子例子比经典例子更强大。然而,由Zhang改进的Atici和Servedio表明,在PAC设置中,量子样例不能更强大:所需的量子样例数量为$$ \Omega\Big(\frac{d^{1-\eta}}{\eps} + d + \frac{\log(1/\delta)}{\eps}\Big)\mbox{ for all }\eta> 0. $$。我们的主要结果是,在PAC和不可知论模型中,量子和经典样本复杂性实际上等于常数因子。我们给出了两种方法。第一个是一个相当简单的信息论论证,它产生了上述两个经典边界,并产生了量子样本复杂性的相同边界,直至$\log(d/\eps)$因子。然后,我们给出了第二种避免对数因子损失的方法,基于分析“相当好的测量”在与学习对应的量子态识别问题上的行为。这表明经典和量子样本的复杂性等于常数因子。
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