The Chemistry of Protactinium. IX : A Study of the Solvent Extraction of Protactinium (V) from a Perchloric Acid Solution Using Di (2-ethylhexyl) phosphoric Acid as the Extractant
{"title":"The Chemistry of Protactinium. IX : A Study of the Solvent Extraction of Protactinium (V) from a Perchloric Acid Solution Using Di (2-ethylhexyl) phosphoric Acid as the Extractant","authors":"T. Mitsugashira","doi":"10.1246/BCSJ.44.1305","DOIUrl":null,"url":null,"abstract":"Studies of the chemical behavior of protactinium(V) in a perchloric acid solution were carried out by the HDEHP-benzene extraction method. When the protactinium concentration was lower than 10−7 M, the extraction reaction was considered to proceed as:PaO(OH)2+aq.+ 3(HA)2 org.= PaOp(OH)qA5−2p−q(HA)2p+q+1 org.+ 2H+aq.+ (2–p–q)H2Oaq.where p=1, q=0 or 1, and p=2, q=0andPa(OH)32+aq.+ 3(HA)2 org.= PaOp(OH)qA5−2p−q(HA)2p+q+1 org.+ 2H+aq.+ (3–p-q)H2Oaq.where p=0, q=0, 1, 2, or 3; p=1, q=0 or 1 and p=2, q=0.","PeriodicalId":21586,"journal":{"name":"Science reports of the Research Institutes, Tohoku University. Ser. A, Physics, chemistry and metallurgy","volume":"12 1","pages":"135"},"PeriodicalIF":0.0000,"publicationDate":"1971-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"3","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Science reports of the Research Institutes, Tohoku University. Ser. A, Physics, chemistry and metallurgy","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1246/BCSJ.44.1305","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 3
Abstract
Studies of the chemical behavior of protactinium(V) in a perchloric acid solution were carried out by the HDEHP-benzene extraction method. When the protactinium concentration was lower than 10−7 M, the extraction reaction was considered to proceed as:PaO(OH)2+aq.+ 3(HA)2 org.= PaOp(OH)qA5−2p−q(HA)2p+q+1 org.+ 2H+aq.+ (2–p–q)H2Oaq.where p=1, q=0 or 1, and p=2, q=0andPa(OH)32+aq.+ 3(HA)2 org.= PaOp(OH)qA5−2p−q(HA)2p+q+1 org.+ 2H+aq.+ (3–p-q)H2Oaq.where p=0, q=0, 1, 2, or 3; p=1, q=0 or 1 and p=2, q=0.