A reciprocal relation for Hermite polynomials

Q4 Mathematics New Zealand Journal of Mathematics Pub Date : 2021-12-14 DOI:10.53733/88
S. Nadarajah, C. Withers
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引用次数: 0

Abstract

For $x\in \mathbb{R}$, the ordinary Hermite polynomial $H_k(x)$ can be written\begin{eqnarray*}\displaystyleH_k(x)= \mathbb{E} \left[ (x + {\rm i} N)^k \right] =\sum_{j=0}^k {k\choose j} x^{k-j} {\rm i}^j \mathbb{E} \left[ N^j \right],\end{eqnarray*}where ${\rm i} = \sqrt{-1}$ and $N$ is a unit normal random variable.  We prove the reciprocal relation\begin{eqnarray*}\displaystylex^k=\sum_{j=0}^k {k\choose j} H_{k-j}(x)\ \mathbb{E} \left[ N^j \right].\end{eqnarray*}A similar result is given for the multivariate Hermite polynomial.
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埃尔米特多项式的互反关系
对于$x\in \mathbb{R}$,普通的Hermite多项式$H_k(x)$可以写成\begin{eqnarray*}\displaystyleH_k(x)= \mathbb{E} \left[ (x + {\rm i} N)^k \right] =\sum_{j=0}^k {k\choose j} x^{k-j} {\rm i}^j \mathbb{E} \left[ N^j \right],\end{eqnarray*},其中${\rm i} = \sqrt{-1}$和$N$是一个单位正态随机变量。我们证明了互反关系\begin{eqnarray*}\displaystylex^k=\sum_{j=0}^k {k\choose j} H_{k-j}(x)\ \mathbb{E} \left[ N^j \right].\end{eqnarray*}对于多元Hermite多项式也给出了类似的结果。
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来源期刊
New Zealand Journal of Mathematics
New Zealand Journal of Mathematics Mathematics-Algebra and Number Theory
CiteScore
1.10
自引率
0.00%
发文量
11
审稿时长
50 weeks
期刊最新文献
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