{"title":"从样本看先知不平等:越多越好吗?","authors":"Tomer Ezra","doi":"arxiv-2409.00559","DOIUrl":null,"url":null,"abstract":"We study a variant of the single-choice prophet inequality problem where the\ndecision-maker does not know the underlying distribution and has only access to\na set of samples from the distributions. Rubinstein et al. [2020] showed that\nthe optimal competitive-ratio of $\\frac{1}{2}$ can surprisingly be obtained by\nobserving a set of $n$ samples, one from each of the distributions. In this\npaper, we prove that this competitive-ratio of $\\frac{1}{2}$ becomes\nunattainable when the decision-maker is provided with a set of more samples. We\nthen examine the natural class of ordinal static threshold algorithms, where\nthe algorithm selects the $i$-th highest ranked sample, sets this sample as a\nstatic threshold, and then chooses the first value that exceeds this threshold.\nWe show that the best possible algorithm within this class achieves a\ncompetitive-ratio of $0.433$. Along the way, we utilize the tools developed in\nthe paper and provide an alternative proof of the main result of Rubinstein et\nal. [2020].","PeriodicalId":501316,"journal":{"name":"arXiv - CS - Computer Science and Game Theory","volume":"45 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-08-31","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Prophet Inequality from Samples: Is the More the Merrier?\",\"authors\":\"Tomer Ezra\",\"doi\":\"arxiv-2409.00559\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"We study a variant of the single-choice prophet inequality problem where the\\ndecision-maker does not know the underlying distribution and has only access to\\na set of samples from the distributions. Rubinstein et al. [2020] showed that\\nthe optimal competitive-ratio of $\\\\frac{1}{2}$ can surprisingly be obtained by\\nobserving a set of $n$ samples, one from each of the distributions. In this\\npaper, we prove that this competitive-ratio of $\\\\frac{1}{2}$ becomes\\nunattainable when the decision-maker is provided with a set of more samples. We\\nthen examine the natural class of ordinal static threshold algorithms, where\\nthe algorithm selects the $i$-th highest ranked sample, sets this sample as a\\nstatic threshold, and then chooses the first value that exceeds this threshold.\\nWe show that the best possible algorithm within this class achieves a\\ncompetitive-ratio of $0.433$. Along the way, we utilize the tools developed in\\nthe paper and provide an alternative proof of the main result of Rubinstein et\\nal. [2020].\",\"PeriodicalId\":501316,\"journal\":{\"name\":\"arXiv - CS - Computer Science and Game Theory\",\"volume\":\"45 1\",\"pages\":\"\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2024-08-31\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"arXiv - CS - Computer Science and Game Theory\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/arxiv-2409.00559\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - CS - Computer Science and Game Theory","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2409.00559","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
摘要
我们研究了单选预言家不等式问题的一个变体,在这个变体中,决策者不知道基本分布,只能从分布中获取一组样本。鲁宾斯坦等人[2020]的研究表明,通过观察一组 $n$ 样本(每种分布都有一个样本),竟然可以得到 $\frac{1}{2}$ 的最优竞争比。在本文中,我们将证明当决策者获得一组更多的样本时,$\frac{1}{2}$的竞争比率将变得无法实现。我们研究了顺序静态阈值算法的自然类,该算法选择排名最高的第 i 个样本,将该样本设为静态阈值,然后选择超过该阈值的第一个值。我们证明,该类算法中的最佳算法可实现 0.433 美元的竞争比率。在此过程中,我们利用论文中开发的工具,为鲁宾斯坦等人的主要结果提供了另一种证明。[2020].
Prophet Inequality from Samples: Is the More the Merrier?
We study a variant of the single-choice prophet inequality problem where the
decision-maker does not know the underlying distribution and has only access to
a set of samples from the distributions. Rubinstein et al. [2020] showed that
the optimal competitive-ratio of $\frac{1}{2}$ can surprisingly be obtained by
observing a set of $n$ samples, one from each of the distributions. In this
paper, we prove that this competitive-ratio of $\frac{1}{2}$ becomes
unattainable when the decision-maker is provided with a set of more samples. We
then examine the natural class of ordinal static threshold algorithms, where
the algorithm selects the $i$-th highest ranked sample, sets this sample as a
static threshold, and then chooses the first value that exceeds this threshold.
We show that the best possible algorithm within this class achieves a
competitive-ratio of $0.433$. Along the way, we utilize the tools developed in
the paper and provide an alternative proof of the main result of Rubinstein et
al. [2020].