宿主和病原体如何选择防御和反防御的强度?博弈论观点

Shalu Dwivedi, Ravindra Garde, Stefan Schuster
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引用次数: 0

摘要

宿主与病原体之间的相互作用包括病原体的攻击、宿主经常采取的防御措施以及病原体可能采取的反防御措施。在此,我们提出一种博弈论方法来描述这种相互作用。具体来说,宿主和病原体可以分别产生毒素和降解毒素的酶,也可以不产生毒素和降解毒素的酶。我们认为宿主和病原体也必须为生产毒素或酶付出代价。我们强调了博弈的顺序版本和非顺序版本,并确定了纳什均衡。此外,我们还解决了博弈中出现的一个悖论。如果灭活酶非常有效,那么生产毒素就变得无用,导致不再需要酶。在博弈论中,这种情况可以用广义的匹配一分钱博弈来描述。作为一项新成果,我们发现了在什么条件下防御周期会导致稳定状态或振荡。对于饱和剂量反应动力学和单调成本函数,我们得到了作为纯纳什均衡的 "部分(反)防御 "策略。这意味着生产适量的毒素和酶是最佳选择。
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How hosts and pathogens choose the strengths of defense and counter-defense. A game-theoretical view
Host-pathogen interactions consist of an attack by the pathogen, frequently a defense by the host and possibly a counter-defense by the pathogen. Here, we present a game-theoretical approach to describing such interactions. We consider a game where the host and pathogen are players and they can choose between the strategies of defense (or counter-defense) and no response. Specifically, they may or may not produce a toxin and an enzyme degrading the toxin, respectively. We consider that the host and pathogen must also incur a cost for toxin or enzyme production. We highlight both the sequential and non-sequential versions of the game and determine the Nash equilibria. Further, we resolve a paradox occurring in that interplay. If the inactivating enzyme is very efficient, producing the toxin becomes useless, leading to the enzyme being no longer required. Then, production of the defense becomes useful again. In game theory, such situations can be described by a generalized matching pennies game. As a novel result, we find under which conditions the defense cycle leads to a steady state or to an oscillation. We obtain, for saturating dose-response kinetics and considering monotonic cost functions, 'partial (counter-)defense' strategies as pure Nash equilibria. This implies that producing a moderate amount of toxin and enzyme is the best choice.
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