快击剑

Mikkel Abrahamsen, Anna Adamaszek, K. Bringmann, Vincent Cohen-Addad, M. Mehr, E. Rotenberg, A. Roytman, M. Thorup
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引用次数: 5

摘要

我们考虑的是Capoyleas、Rote、Woeginger、Arkin、Khuller和Mitchell在90年代初研究过的非常自然的“围栏”问题。给定平面上的n个点的集合S,我们的目标是找到一组闭曲线,这样(1)每个点都被一条曲线包围,(2)曲线的总长度最小。我们考虑两种主要的变体。在第一种变体中,除了曲线的总长度外,我们还要为每条曲线支付单位成本。这个版本的等效公式是,我们必须封闭n个单位磁盘,只支付封闭曲线的总长度。在另一种变体中,我们允许最多使用k条封闭曲线,并且每条曲线不付出任何代价。对于最多有k条闭合曲线的变量,我们给出了一种对k条闭合曲线都是多项式的算法。对于每条曲线或单位磁盘的代价为单位的变量,我们提出了近似线性时间算法。Capoyleas, Rote和Woeginger在nO(k)时间内用最多k条曲线解决了这个问题。Arkin, Khuller和Mitchell用它来解指数时间下每条曲线的单位成本。当时,他们推测k曲线的问题对于一般k来说是NP困难的。我们的多项式时间算法驳斥了这一点,除非P等于NP。
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Fast fencing
We consider very natural ”fence enclosure” problems studied by Capoyleas, Rote, and Woeginger and Arkin, Khuller, and Mitchell in the early 90s. Given a set S of n points in the plane, we aim at finding a set of closed curves such that (1) each point is enclosed by a curve and (2) the total length of the curves is minimized. We consider two main variants. In the first variant, we pay a unit cost per curve in addition to the total length of the curves. An equivalent formulation of this version is that we have to enclose n unit disks, paying only the total length of the enclosing curves. In the other variant, we are allowed to use at most k closed curves and pay no cost per curve. For the variant with at most k closed curves,we present an algorithm that is polynomialin bothn andk. For the variant with unit cost per curve, or unit disks, we presenta near-linear time algorithm. Capoyleas, Rote, and Woeginger solved the problem with at most k curves in nO(k) time. Arkin, Khuller, and Mitchell used this to solve the unit cost per curve version in exponential time. At the time, they conjectured that the problem with k curves is NP-hard for general k. Our polynomial time algorithm refutes this unless P equals NP.
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