R. Sanjeev, R. Ravi, D. A. Padmavathi, V. Jagannadham
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引用次数: 0
摘要
用简单的直线图外推法计算了两种阳离子(ch2n5 +)和(hn6 +) (eqn)的pkah。1和2)两个假设的分子戊嗪(chn5)和己嗪(n6)。这是通过简单地外推质子化吡啶,吡啶嗪,s-三嗪和1,2,4,5-四嗪的pkah图的轨迹与环嘧啶的氮原子数的关系来实现的。从pkah与中性氮的平均电离电位(I v /eV)曲线的轨迹外推,发现这两种化合物的pkah值甚至非常匹配。这篇文章对于解释酸碱性质和确定pkah值在研究生的研究课堂上是有用的。
pKaH of the Two Conjugate Acids (CH2N5+) and (HN6+) of Two Hypothetical Molecules the Pentazine (CHN5) and the Hexazine (N6) of Azabenzene Series: A Chemical Education Perspective
Extrapolation of a simple straight-line graph is used to calculate the p K aH of two cations (CH 2 N 5+ ) and (HN 6 + ) (eqn. 1 and 2) of two hypothetical molecules pentazine (CHN 5 ) and hexazine (N 6 ). This is achieved by simply an extrapolation of the locus of the plot of p K aH of protonated pyridine, pyridazines, s-triazine and 1,2,4,5-tetrazine versus the number of nitrogen atoms of the cyclic azines. Even well matched p K aH values for these two species were found from the extrapolation of the locus of the plot of p K aH versus average ionization potential (I v /eV) of the neutral azines. This article is useful in graduate research classroom to explain the acid-base properties and to determine the p K aH values.