Collatz dynamics is partitioned by residue class regularly

IF 1.3 Q2 EDUCATION & EDUCATIONAL RESEARCH Research in Mathematics Education Pub Date : 2023-10-19 DOI:10.1080/27684830.2023.2269657
Wei Ren
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Abstract

We propose reduced Collatz conjecture that is equivalent to Collatz conjecture, which states that every positive integer can return to an integer less than it, instead of 1. Reduced Collatz conjecture is easier to explore because certain structures must be presented in reduced dynamics, rather than in original dynamics (as original dynamics is a mixture of original dynamics). Reduced dynamics is a computation sequence from starting integer to the first integer less than it, in terms of “I” that represents (3×+1)/2 and “O” that represents x/2. We formally prove that all positive integers are partitioned into two halves and either present “I” or “O” in next ongoing computation. More specifically, (1) if any positive integer x that is i module 2t (i is an odd integer) is given, then the first t computations (each one is either “I” or “O” corresponding to whether current integer is odd or even) will be identical with that of i. (2) If current integer after t computations (in terms of “I” or “O”) is less than x, then reduced dynamics of x is available. Otherwise, the residue class of x (namely i module 2t) can be partitioned into two halves (namely i module 2t+1 and i+2t module 2t+1), and either half presents “I” or “O” in the intermediately forthcoming (t + 1)-th computation. This discovery will be helpful to the final proof of Collatz conjecture—if the union of residue classes who present reduced dynamics that become larger with the growth of residue module, equals all positive integers asymptotically, then reduced Collatz conjecture (or equivalently, Collatz conjecture) will be true.
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Collatz动力学是按剩余类规则划分的
我们提出了等价于Collatz猜想的简化Collatz猜想,即每个正整数都可以返回到小于它的整数,而不是返回到1。简化Collatz猜想更容易探索,因为某些结构必须以简化动力学呈现,而不是以原始动力学呈现(因为原始动力学是原始动力学的混合)。简化动力学是一个计算序列,从开始的整数到比它小的第一个整数,以“I”表示(3x +1)/2,“O”表示x/2。在接下来的计算中,我们正式证明了所有正整数都被分割成两半,并且要么呈现“I”,要么呈现“O”。更具体地说,(1)如果给定任意一个正整数x为i模2t (i为奇数),则前t次计算(每次计算为“i”或“O”,对应当前整数是奇数还是偶数)将与i的计算相同。(2)如果t次计算后的当前整数(以“i”或“O”表示)小于x,则可以进行x的化简动态。否则,x的残数类(即i模2t)可以分成两半(即i模2t+1和i+2t模2t+1),其中一半在中间即将到来的(t +1)次计算中表示为“i”或“O”。这一发现将有助于Collatz猜想的最终证明——如果呈现随剩余模增长而变大的约简动力学的剩余类的并集渐近地等于所有正整数,则约简Collatz猜想(或等价地,Collatz猜想)为真。
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来源期刊
Research in Mathematics Education
Research in Mathematics Education EDUCATION & EDUCATIONAL RESEARCH-
CiteScore
3.00
自引率
15.40%
发文量
40
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