Ru, Sn和Hf氧化薄膜的极紫外二次电子产率测量

IF 1.5 2区 物理与天体物理 Q3 ENGINEERING, ELECTRICAL & ELECTRONIC Journal of Micro/Nanolithography, MEMS, and MOEMS Pub Date : 2019-07-01 DOI:10.1117/1.JMM.18.3.033501
J. M. Sturm, Feng Liu, E. Darlatt, M. Kolbe, A. Aarnink, Christopher J. Lee, F. Bijkerk
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引用次数: 2

摘要

摘要背景:材料的二次电子产率(SEY)在纳米粒子光刻胶和极紫外光(EUV)光学污染等领域具有重要意义。目的:通过实验测量Ru、Sn和Hf氧化物的SEY和二次电子能量分布。方法:测量薄膜氧化物或具有天然氧化物的薄膜在65至112 eV EUV辐射下的SEY和能量分布。结果:所研究材料的总SEY可以用(天然)氧化物最上层纳米的EUV吸收来解释。结论:虽然Ru和Sn的相对SEY可以很好地解释为EUV吸收性能的差异,但HfO2的SEY几乎比预期高2倍。根据二次电子的能量分布,这可能与较低的二次电子发射势垒有关。
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Extreme UV secondary electron yield measurements of Ru, Sn, and Hf oxide thin films
Abstract. Background: The secondary electron yield (SEY) of materials is important for topics as nanoparticle photoresists and extreme ultraviolet (EUV) optics contamination. Aim: Experimentally measure SEY and secondary electron energy distributions for Ru, Sn, and Hf oxide. Approach: The SEY and energy distribution resulting from 65 to 112 eV EUV radiation are measured for thin-film oxides or films with native oxide. Results: The total SEY can be explained by EUV absorption in the topmost nanometer of (native) oxide of the investigated materials. Conclusions: Although the relative SEY of Ru and Sn is well-explained by the difference in EUV absorption properties, the SEY of HfO2 is almost a factor 2 higher than expected. Based on the energy distribution of secondary electrons, this may be related to a lower barrier for secondary electron emission.
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来源期刊
CiteScore
3.40
自引率
30.40%
发文量
0
审稿时长
6-12 weeks
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