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The Discrete Mathematical Charms of Paul Erdős最新文献

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A Few Tricks of the Trade 这个行业的一些技巧
Pub Date : 2021-08-01 DOI: 10.1017/9781108912181.015
V. Chvátal
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引用次数: 0
More on Erdős 更多信息请访问Erdős
Pub Date : 2021-08-01 DOI: 10.1017/9781108912181.017
V. Chvátal
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引用次数: 0
Discrete Geometry and Spinoffs 离散几何及其衍生
Pub Date : 2021-08-01 DOI: 10.1017/9781108912181.005
V. Chvátal
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引用次数: 0
Definitions, Terminology, Notation 定义、术语、符号
Pub Date : 2021-08-01 DOI: 10.1017/9781108912181.016
V. Chvátal
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引用次数: 0
Thresholds of Graph Properties 图属性阈值
Pub Date : 2021-08-01 DOI: 10.1017/9781108912181.013
V. Chvátal
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引用次数: 0
A Glorious Beginning: Bertrand’s Postulate
Pub Date : 2021-07-31 DOI: 10.1017/9781108912181.004
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引用次数: 0
Index 指数
Pub Date : 2021-07-31 DOI: 10.1017/9781108912181.019
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引用次数: 0
Hamilton Cycles 汉密尔顿周期
Pub Date : 2021-07-31 DOI: 10.1017/9781108912181.014
Frank de Zeeuw
Let us prove that it has no 10-cycle, so the circumference is 9. We think of the Petersen graph as an outside 5-cycle and an inside 5-cycle, connected by 5 links. A 10-cycle would have to contain an even number of such links, and not 0 since then we would not get a connected subgraph. Up to isomorphism, this leaves the two cases below: two links or four links (depicted with thick black edges); note that in the case of two links, they must hit adjacent vertices on one of the two 5-cycles, so after possibly swapping the 5-cycles, this is the only case with two links. In each case, we mark edges that cannot be in the cycle with red, and edges that must be in the cycle with green. Whenever a vertex has a red edge, its other two edges must be green or black. And if two edges of a vertex are green or black, then the third edge must be red. In this way we get a contradiction in both cases, either because of a vertex of degree 3 or because of a 5-cycle.
我们来证明它没有10圆,所以周长是9。我们认为彼得森图是一个外5环和一个内5环,由5个连杆连接。一个10环必须包含偶数个这样的链接,而不是0,因为那样我们就不会得到连通子图。直到同构,这留下了下面两种情况:两个链接或四个链接(用粗黑色边缘描绘);请注意,在两个链接的情况下,它们必须在两个5-cycle中的一个上碰到相邻的顶点,所以在可能交换5-cycle之后,这是两个链接的唯一情况。在每种情况下,我们用红色标记不可能在循环中的边,用绿色标记必须在循环中的边。当一个顶点有一条红色边时,它的另外两条边必须是绿色或黑色。如果一个顶点的两条边是绿色或黑色的,那么第三条边一定是红色的。这样,我们在两种情况下都得到了一个矛盾,要么是因为顶点的次数是3,要么是因为5环。
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引用次数: 8
Ramsey’s Theorem 拉姆齐定理
Pub Date : 2021-07-31 DOI: 10.1017/cbo9780511803888.011
Tom Ridge
The infinite form of Ramsey’s Theorem is proved following Boolos and Jeffrey, Chapter 26.
根据Boolos和Jeffrey在第26章的论述,证明了Ramsey定理的无限形式。
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引用次数: 2
The Friendship Theorem 友谊定理
Pub Date : 2021-07-31 DOI: 10.1017/9781108912181.011
E. Walker
. . . in other words, if every pair of people at a party shares exactly one mutual friend at the party then some guest is a friend of everybody present. More is is true: friendships must be arranged in triangles which intersect only in the universally popular guest. So the graphs satisfying the hypothesis of the theorem are those shown on the immediate right, usually known as ‘windmill’ graphs.
……换句话说,如果聚会上的每一对人恰好有一个共同的朋友,那么某个客人就是在场所有人的朋友。还有一点是正确的:友谊必须排成三角形,只有在普遍受欢迎的客人中才相交。所以满足定理假设的图就是右边的那些,通常被称为“风车图”。
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引用次数: 0
期刊
The Discrete Mathematical Charms of Paul Erdős
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