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The Musical Work as a “Manifold” 音乐作品的“歧义”
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.24
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引用次数: 0
Derivative IX: 第九阶导数:
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.25
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引用次数: 0
Index 指数
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.37
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引用次数: 0
The Vectors of the Body 身体的载体
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.22
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引用次数: 0
Derivative VIII: 导数八世:
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.23
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引用次数: 0
Derivative IV: 四:导数
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.14
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引用次数: 0
Derivative III: 第三导数:
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.13
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引用次数: 0
The Problem of Resemblance 相似的问题
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.7
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引用次数: 0
Derivative II: 导数II:
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.10
S. Crane
Continuation of About Derivatives, this module will teach properties so one could find the derivative of more complicated functions
关于导数的延续,这个模块将教授一些性质,以便人们可以找到更复杂函数的导数
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引用次数: 0
Derivative I: 我:导数
Pub Date : 2018-07-10 DOI: 10.2307/j.ctv4s7jp2.8
Lemma, Let K = A B B T C
Let Λ γ denote the Dirichlet-to-Neumann map for an electrical network with conductivity γ. By way of the Kirchhoff matrix K = (κ ij), consider the space of conductivities to be a subset of R N ×N , where N is the number of vertices, We donote the map from γ to Λ γ by L. In this note we compute the directional derivative D L of L. A direction in this context is represented by a matrix , with arbitrary real entries, which is symmetric and has row sum 0. where is symmetric, has row sum 0, and K is a Kirchhoff matrix. Let K(t) = A + tt A B + tt B B T + tt T B C + tt C , and Λ(t) = A + tt A − (B + tt B)(C + tt C) −1 (B T + tt T B). Then D L = Λ (0) = A − B C −1 B T − BC −1 T B + BC −1 C C −1 B T. Proof. Let C(t) = C + tt C. Notice C(t)(C(t)) −1 = I. By the product rule C (t)C(t) + C(t)(C(t) −1) = 0, hence (C −1) (0) = −C −1 C C −1. Using the product rule again
设Λ γ表示电导率为γ的电网络的Dirichlet-to-Neumann映射。通过Kirchhoff矩阵K = (κ ij),考虑电导率空间是R N ×N的一个子集,其中N是顶点数,我们用L表示从γ到Λ γ的映射。在本文中,我们计算L的方向导数D L。在这种情况下,方向由一个矩阵表示,具有任意实数项,它是对称的,行和为0。其中是对称的,行和为0,K是基尔霍夫矩阵。设K(t) = A + tt A B + tt B B t + tt t BC + tt C, Λ(t) = A + tt A - (B + tt B)(C + tt C) - 1 (B t + tt B),则dl = Λ(0) = A - BC - 1 B t - BC - 1 t B + BC - 1 C C - 1 B t证明。设C(t) = C + tt C,注意C(t)(C(t))−1 = i,根据乘法法则C(t) C(t) + C(t)(C(t)−1)= 0,因此(C−1)(0)= - C−1 C C−1。再次使用乘法法则
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引用次数: 0
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