Victoria Caranfil, E. Rusu, F. Onea, Dunărea de Jos
The objective of the present work is to estimate the benefits which may be obtained from the implementation of a solar and wind project, by considering several reference sites, located in the southeastern part of Romania. In the first case study, the attractiveness of the solar energy will be evaluated for a production factory located in the vicinity of Galati city. The seasonal and annual fluctuation of solar energy will be discussed, by taking also into account the performances of a photovoltaic panel, which may be installed on the roof of these production halls. As for the second case study, the performances of some state-of-the-art wind turbines will be evaluated by taking into account three sites located along the Romanian shoreline, namely Sf. Gheorghe, Navodari and Vama Veche, respectively. According to these results, it was noticed that the photovoltaic panels will partially cover the energy demand for the selected factory, while in the case of wind energy, a single wind turbine defined by a rated capacity of 3 MW seems to easily cover the local electricity budget, reported in Sf. Gheorghe and Vama Veche.
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Cătălin Fatair, A. Nedelcu, M. Dumitrache, Naval Transport
Me ch anical Te s ting and Di agnosis IS S N 2247 – 9635, 2018 (VIII), Volume 2, pp. 11-14 IMPROVING THE HEAT BALANCE BY USING THE EXHAUST GASES FOR A TANKER SHIP Article DOI : https://doi.org/10.35219/mtd.2018.2.02 Catalin FAITAR1)*, Andra Teodora NEDELCU2), Mihail Lucian DUMITRACHE1) 1) Maritime Univers ity of Cons tanta, Faculty of Naval Electromechanics , 104 Mircea cel Batran, RO-900663, Cons tanta, Romania 2) Mircea cel Batran Naval Academy, Faculty of Navigation and Naval Trans port, 1 Fulgerului, RO-900218, Cons tanta, Romania * Corres ponding author: catalinfaitar@yahoo.ro ABSTRACT Exhaust gas energy recovery is more preferred than the energy contained in the cooling water. This is determined by the higher exhau st gas temperature, from 250 °C to 400 °C, for two-strok e engines and from 400 °C to 500 °C for four-strok e engines. Recovery is accomplished by means of a heat exchanger, called a heat recovery boiler or directly from the exhaust gas by the entrainment of a power turbine that drives an electric generator. Mitsubishi engines waste recovery systems consist of high-quality, highly efficient machinery that significantly increases ov erall vessel efficiency and it is an effective way to reduce th e EEDI (energy efficiency design index ). Very large crude carriers (VLCC) are among the biggest work ing freight vessels on the planet. With a capacity more than 250,000 dwt, these big ve ssels are equipped with two -strok e engines of high power. Keywor ds : heat, recovery, engine, boiler, parameters 1. INTRODUCTIO N The abs olute thermal balance is us ed when it comes to analyze the us e of thermal energy on a particular engine, while the s p ecific heat balance, as well as the relative thermal balance, are us ed both for analyzing the us e of thermal energy and for comparing, in terms of effective efficiency, one engine to another. The dis tribution of the heat flows for a particular operating regime of an engine is repres ented graphically in Fig. 1. This figure s hows the heat balance diagram in which the heat flows are divided into components corres ponding to the real s ituation. The los t heat flow, Qpd , is : Qpd =Qint ‐(Qu +Qpr +Qpg ) (1)
中国船舶工程学报，2018(8)，第2卷，第11-14页。利用废气改善油轮的热平衡https://doi.org/10.35219/mtd.2018.2.02 Catalin FAITAR1)*， Andra Teodora NEDELCU2)， Mihail Lucian DUMITRACHE1) 1)康坦塔海事大学，海军机电学院，104 Mircea cel Batran, RO-900663，康坦塔，罗马尼亚2)Mircea cel Batran海军学院，航海与海军运输学院，1 Fulgerului, RO-900218，康坦塔，罗马尼亚*catalinfaitar@yahoo.ro摘要废气的能量回收比冷却水所含的能量更可取。这是由较高的排气温度决定的，从250°C到400°C，对于二冲程发动机和从400°C到500°C的四冲程发动机。回收是通过称为热回收锅炉的热交换器或通过驱动发电机的动力涡轮机的牵引直接从废气中完成的。三菱发动机废弃物回收系统由高质量、高效率的机械组成，可显著提高船舶整体效率，是降低EEDI(能效设计指数)的有效途径。超大型原油运输船(VLCC)是世界上最大的货运船之一。这些大型船舶的容量超过25万载重吨，配备了大功率二冲程发动机。关键词:热能，回收，发动机，锅炉，参数在分析特定发动机的热能消耗时，需要绝对热平衡，而在分析热能消耗和比较发动机的有效效率时，需要比热平衡和相对热平衡。图1用图形表示了发动机在特定工作状态下的热流分布。该图显示了热平衡图，其中热流根据实际情况被分成了不同的分量。损失热流Qpd = Qpd‐(Qu +Qpr +Qpg) (1)
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