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On a Mathematical Model for an Old Card Trick 关于一个老纸牌魔术的数学模型
Pub Date : 2017-05-24 DOI: 10.1515/rmm-2017-0014
Roy Quintero
Abstract The three-pile trick is a well-known card trick performed with a deck of 27 cards which dates back to the early seventeenth century at least and its objective is to uncover the card chosen by a volunteer. The main purpose of this research is to give a mathematical generalization of the three-pile trick for any deck of ab cards with a, b ≥ 2 any integers by means of a finite family of simple discrete functions. Then, it is proved each of these functions has just one or two stable fixed points. Based on this findings a list of 222 (three-pile trick)-type brand new card tricks was generated for either a package of 52 playing cards or any appropriate portion of it with a number of piles between 3 and 7. It is worth noting that all the card tricks on the list share the three main properties that have characterized the three-pile trick: simplicity, self-performing and infallibility. Finally, a general performing protocol, useful for magicians, is given for all the cases. All the employed math techniques involve naive theory of discrete functions, basic properties of the quotient and remainder of the division of integers and modular arithmetic.
三桩牌魔术是一种著名的纸牌魔术,一副27张牌,至少可以追溯到17世纪初,其目的是揭开志愿者选择的牌。本研究的主要目的是利用有限族的简单离散函数,对任意整数a, b≥2的任意一副ab牌的三桩技巧进行数学推广。然后,证明了每个函数只有一个或两个稳定不动点。基于这一发现,我们为一组52张纸牌或其中任何适当部分(纸牌数在3到7之间)的纸牌生成了222种(三堆牌)类型的全新纸牌戏法。值得注意的是,列表上的所有纸牌戏法都有三个特征:简单、自演和绝对正确。最后,给出了一种适用于魔术师的通用表演规程。所有使用的数学技巧都涉及离散函数的朴素理论,整数除法的商和余数的基本性质以及模算术。
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引用次数: 0
Rules for folding polyminoes from one level to two levels 从一层到两层折叠多米诺的规则
Pub Date : 2017-01-12 DOI: 10.1515/rmm-2017-0020
Julia Martín, Elizabeth Wilcox
Abstract Polyominoes have been the focus of many recreational and research investigations. In this article, the authors investigate whether a paper cutout of a polyomino can be folded to produce a second polyomino in the same shape as the original, but now with two layers of paper. For the folding, only “corner folds” and “half edge cuts” are allowed, unless the polyomino forms a closed loop, in which case one is allowed to completely cut two squares in the polyomino apart. With this set of allowable moves, the authors present algorithms for folding different types of polyominoes and prove that certain polyominoes can successfully be folded to two layers. The authors also establish that other polyominoes cannot be folded to two layers if only these moves are allowed.
多利骨牌一直是许多娱乐和研究调查的焦点。在这篇文章中,作者研究了剪纸的多聚体是否可以折叠成与原始形状相同的第二个多聚体,但现在有两层纸。对于折叠,只允许“角折”和“半边切”,除非多形图形成一个闭环,在这种情况下,允许将多形图中的两个正方形完全分开。利用这组允许的移动,作者提出了折叠不同类型多角的算法,并证明了某些多角可以成功地折叠成两层。作者还证明,如果只允许这些移动,其他多骨牌就不能折叠成两层。
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引用次数: 0
Quantum Distribution of a Sudoku Key 数独密钥的量子分布
Pub Date : 2016-12-01 DOI: 10.1515/rmm-2016-0009
Sian K. Jones
Abstract Sudoku grids are often cited as being useful in cryptography as a key for some encryption process. Historically transporting keys over an alternate channel has been very difficult. This article describes how a Sudoku grid key can be secretly transported using quantum key distribution methods whereby partial grid (or puzzle) can be received and the full key can be recreated by solving the puzzle.
摘要数独网格在密码学中经常被认为是有用的,可以作为某些加密过程的密钥。从历史上看,通过备用信道传输密钥是非常困难的。本文描述了如何使用量子密钥分发方法秘密传输数独网格密钥,即可以接收部分网格(或谜题),并通过解决谜题重新创建完整的密钥。
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引用次数: 1
Where are (Pseudo)Science Fool’s Hoax Articles in April From? 四月(伪)科学傻瓜的恶作剧文章从何而来?
Pub Date : 2016-12-01 DOI: 10.1515/rmm-2016-0007
Tereza Bártlová
Abstract In this paper, we discuss in detail what is behind April Fool’s Day
在本文中,我们详细讨论了愚人节的背后是什么
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引用次数: 0
The Maximum Queens Problem with Pawns 有兵的最大皇后问题
Pub Date : 2016-12-01 DOI: 10.1515/rmm-2016-0010
D. Chatham
Abstract The classic n-queens problem asks for placements of just n mutually non-attacking queens on an n × n board. By adding enough pawns, we can arrange to fill roughly one-quarter of the board with mutually non-attacking queens. How many pawns do we need? We discuss that question for square boards as well as rectangular m × n boards.
经典的n皇后问题要求在一个n × n的棋盘上放置n个互不攻击的皇后。通过添加足够的小兵,我们可以安排将大约四分之一的棋盘填满互不攻击的皇后。我们需要多少小兵?我们讨论了方形板和矩形m × n板的问题。
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引用次数: 2
Designing Peg Solitaire Puzzles 设计挂钩纸牌谜题
Pub Date : 2016-08-04 DOI: 10.1515/rmm-2017-0011
George I. Bell
Abstract Peg solitaire is an old puzzle with a 300 year history. We consider two ways a computer can be utilized to find interesting peg solitaire puzzles. It is common for a peg solitaire puzzle to begin from a symmetric board position, we have computed solvable symmetric board positions for four board shapes. A new idea is to search for board positions which have a unique starting jump leading to a solution. We show many challenging puzzles uncovered by this search technique. Clever solvers can take advantage of the uniqueness property to help solve these puzzles.
摘要:挂钩纸牌是一种古老的纸牌游戏,已有300多年的历史。我们考虑了两种方法,可以利用计算机找到有趣的挂钩纸牌谜题。这是常见的钉子纸牌谜题开始从一个对称的棋盘位置,我们已经计算出可解决的对称棋盘位置为四种棋盘形状。一个新的想法是寻找有一个独特的开始跳跃导致一个解决方案的棋盘位置。我们展示了通过这种搜索技术发现的许多具有挑战性的谜题。聪明的解决者可以利用唯一性属性来帮助解决这些谜题。
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引用次数: 0
Eternal Picaria 永恒的Picaria
Pub Date : 2016-07-14 DOI: 10.1515/rmm-2017-0016
U. Larsson, Israel Rocha
Abstract Picaria is a traditional board game, played by the Zuni tribe of the American Southwest and other parts of the world, such as a rural Southwest region in Sweden. It is related to the popular children’s game of Tic-tac-toe, but the 2 players have only 3 stones each, and in the second phase of the game, pieces are slided, along specified move edges, in attempts to create the three-in-a-row. We provide a rigorous solution, and prove that the game is a draw; moreover our solution gives insights to strategies that players can use.
Picaria是一种传统的棋盘游戏,由美国西南部和世界其他地区的祖尼部落,如瑞典西南部的农村地区玩。它与流行的儿童游戏“一字棋”(tic - tactoe)有关,但两名玩家每人只有3颗石头,在游戏的第二阶段,棋子沿着指定的移动边缘滑动,试图形成一排三。我们提供了一个严格的解决方案,并证明了游戏是平局;此外,我们的解决方案还提供了玩家可以使用的策略。
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引用次数: 3
Finding the Year’s Share in Day-of-Week Calculations 在星期计算中找到一年的份额
Pub Date : 2016-05-22 DOI: 10.1515/rmm-2016-0008
S. Abdali
Abstract The dominant part in the mental calculation of the day of the week for any given date is to determine the year share, that is, the contribution of the two-digit year part of the date. This paper describes a number of year share computation methods, some well-known and some new. The “Parity Minus 3” method, in particular, is a new alternative to the popular “Odd+11” method. The paper categorizes the methods of year share computation, and presents simpler proofs of their correctness than usually provided.
在心算任何给定日期的星期几时,最主要的部分是确定年份份额,即日期的两位数年份部分的贡献。本文介绍了许多年份额的计算方法,有些是比较知名的,有些是比较新的。特别是“奇偶校验- 3”方法,是流行的“奇数+11”方法的新替代方案。本文对年份额计算方法进行了分类,并给出了比一般方法更简单的正确性证明。
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引用次数: 0
Construction and Enumeration of Circuits Capable of Guiding a Miniature Vehicle 微型飞行器导航电路的构建与枚举
Pub Date : 2016-03-29 DOI: 10.1515/rmm-2016-0006
J. Bastien
Abstract In contrast to traditional toy tracks, a patented system allows the creation of a large number of tracks with a minimal number of pieces, and whose loops always close properly. These circuits strongly resemble traditional self-avoiding polygons (whose explicit enumeration has not yet been resolved for an arbitrary number of squares) yet there are numerous differences, notably the fact that the geometric constraints are different than those of self-avoiding polygons. We present the methodology allowing the construction and enumeration of all of the possible tracks containing a given number of pieces. For small numbers of pieces, the exact enumeration will be treated. For greater numbers of pieces, only an estimation will be offered. In the latter case, a randomly construction of circuits is also given. We will give some routes for generalizations for similar problems.
与传统的玩具轨道相比,一种专利系统允许用最少的部件创建大量的轨道,并且其循环总是正确关闭。这些电路非常类似于传统的自避多边形(其显式枚举尚未解决任意数量的正方形),但有许多不同之处,特别是几何约束与自避多边形的几何约束不同。我们提出的方法允许建设和枚举所有可能的轨道包含一个给定数量的碎片。对于少量的块,将处理精确枚举。对于更大数量的件,只有一个估计将提供。在后一种情况下,也给出了电路的随机构造。我们将给出一些推广类似问题的途径。
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引用次数: 3
Who is Guilty? 谁有罪?
Pub Date : 2016-03-23 DOI: 10.2478/rmm-2021-0010
B. Chen, Ezra Erives, Leon Fan, Michael Gerovitch, Jonathan Hsu, T. Khovanova, Neil Malur, Ashwin Padaki, Nastia Polina, Will Sun, Jacob Tan, Andrew The
Abstract We discuss a generalization of logic puzzles in which truth-tellers and liars are allowed to deviate from their pattern in case of one particular question: “Are you guilty?”
摘要:我们讨论了一种逻辑谜题的概括,在这种逻辑谜题中,诚实者和说谎者被允许在一个特定的问题上偏离他们的模式:“你有罪吗?”
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引用次数: 0
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Recreational Mathematics Magazine
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